Question

Write a program that will calculate the sum of the first n odd integers, and the

sum of the first n even integers.

Use a Do while loop

Use a for loop

Here is a sample of how the program should run:

How many odd integers would you like to add? 5

Count Odd Integer Sum

1 1 1

2 3 4

3 5 9

4 7 16

5 9 25

The sum of the first 5 odd integers is 25

How many even integers would you like to add? 7

Count Even Integer Sum

1 2 2

2 4 6

3 6 12

4 8 20

5 10 30

6 12 42

7 14 56

The sum of the first 7 even integers is 56

Do you want to add again? Press y or n

y

How many odd integers would you like to add?

Make sure your program works with any input value from 1 to 1000.

REMEMBER! The sum of the first 5 odd integers is 1 + 3 + 5 + 7 + 9. It is NOT the

sum of the odd integers up to 5

Answer 1

Code:

#include<stdio.h>
int main(){
   int i=1, sum=0, upto;
   char again;
   while(again!='n'){
       printf("How many odd integers would you like to add?");
       scanf("%d",&upto);
       int j=1;
       printf("count odd integer sum\n");
       do {
           sum=sum+i;
           printf("%d %d %d\n",j,i,sum);
           j++;
           i=i+2;
       }while(j<=upto);
      
       printf("The sum of the first %d odd integers is %d\n",upto,sum);
      
       printf("How many even integers would you like to add?");
       scanf("%d",&upto);
       sum=0;
       j=2;
       printf("count even integer sum\n");
       for(i=1;i<=upto;i++){
           j=i*2;
           sum=sum+j;
           printf("%d %d %d\n",i,j,sum);
       }
      
       printf("The sum of the first %d even integers is %d\n",upto,sum);
       printf("Do you want to add again? Press y or n\n");
       scanf("%s",&again);
   }
  
   return 0;
}

Output:

Code with explanation: