In: Statistics and Probability
Employers often use standardized measures to gauge how likely it is that a new employee with little to no experience will succeed in their company. One such factor is intelligence, measured using the Intelligence Quotient (IQ). To show that this factor is related to job success, an organizational psychologist measures the IQ score and job performance (in units sold per day) in a sample of 10 new employees.
IQ | Job Performance |
---|---|
100 | 16 |
115 | 35 |
108 | 32 |
98 | 19 |
120 | 47 |
147 | 54 |
132 | 48 |
85 | 52 |
105 | 23 |
110 | 36 |
(a) Convert the following data to ranks and then compute a
Spearman correlation coefficient. (Round your answer to three
decimal places.)
_____
(b) Using a two-tailed test at a 0.05 level of significance, state
the decision to retain or reject the null hypothesis.
Retain the null hypothesis.
Reject the null hypothesis.
(a)
We make a table
IQ | Job Performance | RankI | RankJ | d=RankI-RankJ | d2 |
100 | 16 | 8 | 10 | -2 | 4 |
115 | 35 | 4 | 6 | -2 | 4 |
108 | 32 | 6 | 7 | -1 | 1 |
98 | 19 | 9 | 9 | 0 | 0 |
120 | 47 | 3 | 4 | -1 | 1 |
147 | 54 | 1 | 1 | 0 | 0 |
132 | 48 | 2 | 3 | -1 | 1 |
85 | 52 | 10 | 2 | 8 | 64 |
105 | 23 | 7 | 8 | -1 | 1 |
110 | 36 | 5 | 5 | 0 | 0 |
Total | N/A | N/A | N/A | 0 | 76 |
The number of observations (n)=10
Spearman's rank correlation coefficient is given by
(b)
Now we perform the correlation test.
The test statistic is given by
The test statistic follows t distribution with df 8
The p-value is obatined as 0.107907
As the p-value is more than 0.05, we fail to reject the null hypothesis i.e. the null hypothesis is retained at 5% level of significance.
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