Tin (atomic radius, r = 1.405 A)and nickel (r = 1.243 A) both dissolve in copper...

Tin (atomic radius, r = 1.405 A)and nickel (r = 1.243 A) both dissolve in copper (r = 1.278 A) by substitution in the copper lattice. Which of these elements added to copper will produce a metal with a higher strength and why?

Expert Solution

Tin(atomic radius, r=1.405A) when dissolve in copper(atomic radius, r=1.278A) produces a metal with higher strength in comparison to metal produced when nickel(atomic radius, r=1.243) is dissolved in copper, this is because when solute atom is large enough then the solvent atom then it replaces the solvent atom in there lattice position, this dislocation creates stress field within the material depending upon their character, when solute solute atoms are introduced, local stress fields are formed that interact with those of dislocations, impending their motion and causing an increase in yield stress of the material, which means an increase in strength of the material, in this case atomic radius of tin is larger than copper whereas atomic radius of nickel is smaller than copper, hence the fact.

samet mamat answered 2 years ago

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