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An 10.6 kg object is pulled along a horizontal surface at constant speed. If the coefficient...

An 10.6 kg object is pulled along a horizontal surface at constant speed. If the coefficient of friction is 0.11, what is the force of friction?

An applied force of 10.9 N [right] provides a 9.46 kg object with a net acceleration of 2.31 m/s2 [right] on a flat surface. What is the magnitude of the force of friction acting on the object?

A 6.2 kg object is pulled along a horizontal surface by a force of 22.0N. If its acceleration is 1.1 m/s2, what is the coefficient of friction between the two surfaces? What is the force of friction? (There are two answers for this question)

Solutions

Expert Solution

1. Normal force on the object will be equal to mg

Thus

2. The friction force acts to oppose the motion of the object being pulled and the net force is what results in the acceleration.

Negative sign shows that friction is opposite to the applied force.

(3)

The friction force acts to oppose the motion of the object being pulled and the net force is what results in the acceleration.

As

Therefore, coefficient of friction is 0.249 and the frictional force is 15.18 N.

genius_generous answered 2 years ago
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