Question

An experienced Python programmer in your company wants your assistance calculating the division of the numerator being the sum of all the multipliers of four divided by the denominator of all the multipliers of three using one for loop and one range statement respectively. Both sums of the numerator and denominator respectively are to be calculated using the same range of numbers between (and including) the number 0 and up to (and including) the number 100. The experienced Python programmer gives you a hint that the answer for the requested division is .77243. Please create the script that uses one for loop and will produce the expected output below. Your code must use a loop to receive credit.

Expect Output:

The sum of all multipliers of 4 is: 1300

The sum of all multipliers of 3 is: 1683

1300 divided by 1683 is 0.7724301841948901

Answer 1

• Below is the detailed implementation of the above problem in PYTHON with code and output shown.
• For better understanding please read the comments mentioned in the code.
• In the code below only a for loop is used with a range statement and the sum of multipliers of 4 and 3 are calculated and the output is printed.
• CODE:

#variable to store sum of multipliers of 4
four=0
#variable to store sum of multipliers of 3
three=0
#for each number from 0 to 100
for i in range(0,100+1):
#if i is divisible by 4
if i%4==0:
four+=i
#if i is divisible by 3
if i%3==0:
three+=i
#printing the output
print("The sum of all multipliers of 4 is: {}".format(four))
print("The sum of all multipliers of 3 is: {}".format(three))
print("{} divided by {} is {}".format(four, three, four/three))

• OUTPUT:

The sum of all multipliers of 4 is: 1300
The sum of all multipliers of 3 is: 1683
1300 divided by 1683 is 0.7724301841948901

• Below are the screenshot attached for the code and output for better clarity and understanding.

CODE and OUTPUT

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