In: Accounting
A machine with an initial purchase price of $29100 has a useful life of 10 years. The usage of this machine is forecasted to bring us the savings in the table below. At an interest rate of 0% how many years will it take to payback the investment?
Year |
1 |
2 |
3 |
4 |
5 |
6 |
7 |
8 |
9 |
10 |
Savings, $ |
7000 |
9000 |
5000 |
3000 |
4000 |
6000 |
5000 |
6000 |
4000 |
7000 |
1-2 years |
||
2-3 years |
||
3-4 years |
||
4-5 years |
||
5-6 years |
||
6-7 years |
||
7-8 years |
||
8-9 years |
||
More than 8 years |
Solution : 1 | |||||
CACULATION OF PPAYBACK PERIOD OF THE INVESTMENT | |||||
YEArs | Particulars | Inflow (Outflow) | Cumulative Value | ||
0 | Outflow | $ -29,100 | $ -29,100 | ||
1 | Inflow | $ 7,000 | $ -22,100 | ||
2 | Inflow | $ 9,000 | $ -13,100 | ||
3 | Inflow | $ 5,000 | $ -8,100 | ||
4 | Inflow | $ 3,000 | $ -5,100 | ||
5 | Inflow | $ 4,000 | $ -1,100 | ||
6 | Inflow | $ 6,000 | $ 4,900 | ||
7 | Inflow | $ 5,000 | $ 9,900 | ||
8 | Inflow | $ 6,000 | $ 15,900 | ||
9 | Inflow | $ 4,000 | $ 19,900 | ||
10 | Inflow | $ 7,000 | $ 26,900 | ||
In the 6th year we recover our all money , but full year is not required for this | |||||
so we can caluclate the exact period of payback | |||||
Payback Period = 5 Years + | $ 1,100 | "/ " By | $ 6,000 | ||
Payback Period = 5 Years + | 0.18 | Years | |||
Payback Period = 5.18 Years | |||||
Answer = Payback period is between 5-6 Years | |||||