In: Chemistry
To predict the hybridization of the molecule by using the below formula,
H=1/2[V+M−C+A]
Where H = number of orbitals in hybridization
V = valence electrons in central atom
C = charge on cation
A = charge on the anion
M = number of monovalent atom
ForSbCl52−, V = 5, A = 2, and M =5
-The number of orbitals in hybridization, H = 1/2[5+5+2] = 6
-Hence, H =6, then SbCl−25 undergoes sp3d2 hybridization.
-Among all given species, SbCl5−2 differs in hybridization
SbCl5²- hybridization is different from others.