Question

- If the hybridization of orbitals on the central atom in a molecule is sp². The electron-domain geometry around this central atom is __________.

- The hybridization of the central atom in the square planar molecule is __________. Determine the type of angle ----------------in such a molecules.

-If the hybridization of central atom in a molecule is sp³, what will be the bond angle and electron domain geometry. __________. -----------,

Answer 1

1) As per VSEPR theory once we know the number of bonds to the central metal atom we can predict the geometry at the central metal atom.

Number of electron groups	Name of electron group geometry
2	linear
3	trigonal-planar
4	tetrahedral
5	trigonal-bipyramidal
6	octahedral

So from this it is clear that if the hybridization is sp2 it means we have 3 bonds. So the electron-domain geometry around this central atom is trigonal-planar.

2) The complete table lists the number of bond the type of geometry and the angles at the central atom

From this table we can see that for square planar geometry the hybridization at the central atom is either sp3d2. It is octahedral with lone pair of electrons on the opposite side of the square planar geometry. The angle between the bonds is 90^o.

• Linear - sp -
• Trigonal planar - sp2
• Tetrahedral - sp3
• Trigonal bipyramidal - dsp3
• Octahedral - sp3d2

3) For Sp3 hybridization the electron domain geometry will be tetrahedral and the bond angle will be 109.5^o.

The table