In: Statistics and Probability
Use the sample data and confidence level given below to complete parts (a) through (d).
A research institute poll asked respondents if they felt vulnerable to identity theft. In the poll,
n=1017
and
x=510
who said "yes." Use a99%
confidence level.
LOADING...
Click the icon to view a table of z scores.
a) Find the best point estimate of the population proportion p.
(Round to three decimal places as needed.)
b) Identify the value of the margin of error E.
(Round to three decimal places as needed.)
c) Construct the confidence interval.
(Round to three decimal places as needed.)
Solution :
n = 1017
x = 510
a ) = x / n =510 / 1017 = 0.501
1 - = 1 - 0.501= 0.499
At 99% confidence level the z is ,
= 1 - 99% = 1 - 0.99 = 0.01
/ 2 = 0.01 / 2 = 0.005
Z/2 = Z0.005 = 2.576
b ) Margin of error = E = Z / 2 * (( * (1 - )) / n)
= 2.576* (((0.501 * 0.499) / 1017)
= 0.040
c ) A 99 % confidence interval for population proportion p is ,
- E < P < + E
0.501 - 0.040 < p < 0.501+ 0.040
0.461 < p < 0.541