In: Statistics and Probability
Use the sample data and confidence level given below to complete parts? (a) through? (d). A research institute poll asked respondents if they felt vulnerable to identity theft. In the? poll, n equals 1013 and x equals 561 who said? "yes." Use a 90 % confidence level.
Solution :
Given that,
n = 1013
x = 561
 = x / n = 561 /1013 = 0.554
1 -
 = 1 - 0.554 = 0.446
At 90% confidence level the z is ,
 = 1 - 90% = 1 - 0.90 = 0.10
 / 2 = 0.10 / 2 = 0.05
Z
/2 = Z0.05 =
1.645
Margin of error = E = Z
 / 2 * ((
 * (1 - 
)) / n)
= 1.645 * (((0.554 * 0.446 ) / 1013 ) =
0.026
A 90 % confidence interval for population proportion p is ,
 - E < P <
 + E
0.554 - 0.026 < p < 0.554 + 0.026
0.528< p < 0.580
The 90% confidence interval for the population proportion p is : ( 0.528 , 0.580)