Question

In: Chemistry

Ethyl alcohol has a vapor pressure of 20.0mm Hg at 8.0 ° C and a normal...

Ethyl alcohol has a vapor pressure of 20.0mm Hg at 8.0 ° C and a normal boiling point of 78.4 ° C.Estimate the vapor pressure at 45 ° C using (a) the Antoine equation; (b) the Clausius – Clapeyronequation and the two given data points; and (c) linear interpolation between the two given points.Taking the fi rst estimate to be correct, calculate the percentage error associated with the secondand third estimates.

Solutions

Expert Solution

According to antoine equation vapor pressure and temperature is related by Antoine eqn as follows.

log P = A - B/(C+T) where A = 8.20417 B= 1642.89 C=230.300

At T= 45oc

Log P = 8.20417-1642.89/(230.300+45) = 2.24

P = 173.78 mm Hg

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By using Causius Clapeyron equation.

ln (P1/P2) = -Hvap/R (1/T1-1/T2)

ln (760/20) = -Hvap/8.314 J/K/mol (1/351.4-1/281)

3.64 = -Hvap/ 8.314 J/K/mol *-7.13 *10^-4

Hvap = 3.64 * 8.314 J/K/mol/ 7.13 *10^-4 = 4.24 *10^4 J/mol

Using the value of Hvap , calculate the vapor pressure at 45oC

ln (P1/P2) = -Hvap/R (1/T1-1/T2)

ln (760/P2) = - (-4.24 *10^4 J/mol)/ 8.314 J/K/mol [1/351.4-1/318]

or, ln (760/P2) = 1.50

or, P2 = 169.64 mm Hg

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Linear extrapolation of the two points is shown below.

According to the above graph the vapor pressure at 45oc is 400mm Hg.

Percet error in second estimate = 173.78-169.64 /173.78 *100 = 2.38 %

Percent error in third estimate = 400-173.78/173.78 *100 = 130%


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