Question

In: Statistics and Probability

Among 180 students of mathematical statistics, 82 did not attend the lecture. The results of the...

Among 180 students of mathematical statistics, 82 did not attend the lecture. The results of the quiz showed that among students who appeared at the lecture 70 students received a positive grade (all students who obtained a positive grade were 95). Examine the appropriate test whether the hypothesis that "passing the quiz is independent of whether the student attends classes" is correct. Assume a significance level of 0.05.

Solutions

Expert Solution

Null hypothesis:Ho:   passing the quiz and whether student attends classes are independent.
alternate hypothesis:Ha: passing the quiz and whether student attends classes are dependent.
degree of freedom(df) =(rows-1)*(columns-1)= 1
for 1 df and 0.05 level , critical value       χ2= 3.841 from excel: chiinv(0.05,1)
Decision rule : reject Ho if value of test statistic X2>3.841
Applying chi square test of independence:
Observed attend not attend Total
pass 70 25 95
not pass 28 57 85
total 98 82 180
Expected Ei=row total*column total/grand total attend not attend Total
pass 51.72 43.28 95
not pass 46.28 38.72 85
total 98 82 180
chi square    χ2 =(Oi-Ei)2/Ei attend not attend Total
pass 6.459 7.719 14.1784
not pass 7.219 8.628 15.8465
total 13.6780 16.3469 30.0249
test statistic X2= 30.025
since test statistic falls in rejection region we reject null hypothesis
we have sufficient evidence to conclude that "passing the quiz is not independent of whether the student attends classes" is correct.

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