In: Chemistry
Do you predict that maltose will reduce cupric ion in Fehling
In chemistry, the Benedict's reaction identifies reducing sugars (those with their free anomeric C-OH), such as glucose or maltose. In alkaline solutions, can reduce Cu2 + which is blue to Cu +, which precipitates from the alkaline solution as Cu2O red-orange.
Benedict's reagent comprises: Cupric sulfate, Sodium Citrate, Anhydrous Sodium Carbonate. (NaOH is used in addition to alkalize the medium)
The basis of this reaction is that in an alkaline medium, the cupric ion (awarded by the cupric sulfate) can be reduced by the effect of sugar aldehyde group (CHO) to form Cu+. This new ion is observed as a brick-red colour precipitate corresponding to cuprous oxide (Cu2O).
The alkaline medium facilitates a linear form, since the sugar ring forms a solution. Once the sugar is linear, the aldehyde group can react with the cupric ion in solution.
In short, there is talk of reducing sugars when they have their free anomeric OH C, and these are what give positive proof of Benedict.