In: Statistics and Probability
| 
 ANOVA  | 
||||
| 
 df  | 
 SS  | 
 MS  | 
 F  | 
|
| 
 Regression  | 
 2  | 
 552.137  | 
 267.069  | 
 24.235  | 
| 
 Residual  | 
 10  | 
 110.22  | 
 11.02  | 
|
| 
 Total  | 
 12  | 
 662.357  | 
||
| 
 Coefficients  | 
 Standard Error  | 
 t Stat  | 
 P-value  | 
|
| 
 Intercept  | 
 -38.623  | 
 3.630  | 
 12.569  | 
 0.000  | 
| 
 Location distance  | 
 0.309  | 
 0.016  | 
 6.552  | 
 0.000  | 
Answer: The following output was obtained from a regression analysis of the dependent variable Sales volume and an independent variable "location distance from the downtown branch.
Solution:
a) Calculate and interpret the correlation coefficient. What does it tell us?
Correlation coefficient, r = √(Regression SS/Total SS)
Correlation coefficient = √552.137/662.357
Correlation coefficient, r = 0.9130.
Interpretation:
There is a strong positive linear relationship between dependent variable Sales volume and independent variable location distance from the downtown branch.
b) Calculate and interpret the coefficient of determination.
Coefficient of determination r^2 = (0.9130)^2
Coefficient of determination, r^2 = 0.8336
Interpretation:
Coefficient of determination explained 83.36% of variation in Sales volume data on location distance from the downtown branch.
c) What is the estimated regression equation?
Y = β0 + β1X
Where, Y - Sales volume
X - Location distance from downtown branch.
Y = - 38.623 + 0.309X.
d)Calculate the estimated sales volume if we open up a store which is 15.6 km away from the central branch in downtown.
When X = 15.6
Y = - 38.623 + 0.309X
Y = - 38.623 + 0.309(15.6)
Y = - 33.8026
Therefore, the estimated sales volume if we open up a store 15.6 km away from the central branch in downtown is -33.8026.