In: Statistics and Probability
| 
 The following regression output was obtained from a study of architectural firms. The dependent variable is the total amount of fees in millions of dollars.  | 
| Predictor | Coef | SE Coef | T | ||||
| Constant | 10.237 | 3.447 | 2.97 | ||||
| X1 | 0.392 | -0.209 | -1.88 | ||||
| X2 | -0.392 | -0.099 | 3.96 | ||||
| X3 | 0.207 | -0.110 | -1.88 | ||||
| X4 | 0.794 | 0.201 | 3.95 | ||||
| X5 | -0.335 | -0.126 | 2.66 | ||||
| Analysis of Variance | ||||||||
| Source | DF | SS | MS | F | ||||
| Regression | 5 | 3710.00 | 742.00 | 15.14 | ||||
| Residual Error | 48 | 2647.38 | 57.55 | |||||
| Total | 53 | 6357.38 | ||||||
| X1 is the number of architects employed by the company. | 
| X2 is the number of engineers employed by the company. | 
| X3 is the number of years involved with health care projects. | 
| X4 is the number of states in which the firm operates. | 
| X5 is the percent of the firm's work that is health care−related. | 
| a. | 
 Write out the regression equation. (Round your answers to 3 decimal places. Negative amounts should be indicated by a minus sign.)  | 
| Ŷ = + X1 + X2 + X3 + X4 + X5. | 
| b. | How large is the sample? How many independent variables are there? | 
| Sample n | |
| Independent variables k | |
| c-1. | 
 State the decision rule for .05 significance level: H0: β1 = β2 = β3 =β4 =β5 =0; H1: Not all β's are 0. (Round your answer to 2 decimal places.)  | 
| Reject H0 if F >___________ | 
| c-2. | Compute the value of the F statistic. (Round your answer to 2 decimal places.) | 
| The computed value of F is__________ | 
| c3. | 
 Can we conclude that the set of regression coefficients could be different from 0? Use the .05 significance level.  | 
| (RejectDo or not Reject)______ H0. (Not all or All)______of the regression coefficients are zero. | 
| For X1 | For X2 | For X3 | For X4 | For X5 | 
| H0: β1 = 0 | H0: β2 = 0 | H0: β3 = 0 | H0: β4 = 0 | H0: β5 = 0 | 
| H1: β1 ≠ 0 | H1: β2 ≠ 0 | H1: β3 ≠ 0 | H1: β4 ≠ 0 | H1: β5 ≠ 0 | 
| d-1. | 
 State the decision rule for .05 significance level. (Negative amounts should be indicated by a minus sign. Round your answers to 3 decimal places.)  | 
| Reject H0 if t < or t > .________ | 
| d-2. | 
 Compute the value of the test statistic. (Round your answers to 2 decimal places. Negative amounts should be indicated by a minus sign.)  | 
| t − value | |
| X1 | |
| X2 | |
| X3 | |
| X4 | |
| X5 | |
| e. | Which variable would you consider eliminating? | 
| Consider eliminating variables_______(X1 and X3), (X2 and X3) , (X3 and X5) , or ( X2 and X5) | 
(a)
The regression model is

(b)
The sample size is:
n= 53+1 = 54
The number of independent variables is: k = 5
(c)
The degree of freedom of numerator: df1=5
The degree of freedom of denominator: df2 =48
The critical value of F using excel function "=FINV(0.05,5,48)" is 2.41.
Reject H0, if F > 2.41
c-2)
The test statistics is
F = 15.14
c-3)
Since F lies in the rejection region so we reject the null hypothesis and we can conclude that at least one coefficient is different from zero.
d-1)
The critical values of t for df = 48 are +/- 2.011.
Rejection region:
If t < -2.011 or t > 2.011, reject H0
Excel function used for critical value "=TINV(0.05,48)"
d-2)
| T | |
| X1 | -1.88 | 
| X2 | 3.96 | 
| X3 | -1.88 | 
| X4 | 3.95 | 
| X5 | 2.66 | 
e)
Since t for X1 and X3 does not lie in the rejection region so these are not significant to the model and we can eliminate them.