Let z denote a random variable having a normal
distribution with ? = 0 and ? = 1. Determine each
of the probabilities below. (Round all answers to four decimal
places.)
(a) P(z < 0.3) =
(b) P(z < -0.3) =
(c) P(0.40 < z < 0.85) =
(d) P(-0.85 < z < -0.40)
=
(e) P(-0.40 < z < 0.85) =
(f) P(z > -1.26) =
(g) P(z < -1.5 or z > 2.50) =
Let z denote a variable that has a standard normal
distribution. Determine the value z* to satisfy the
following conditions. (Round all answers to two decimal
places.)
(a) P(z < z*) = 0.0244
z* =
(b) P(z < z*) = 0.0097
z* =
(c) P(z < z*) = 0.0484
z* =
(d) P(z > z*) = 0.0208
z* =
(e) P(z > z*) = 0.0097
z* =
(f) P(z > z* or z <
−z*) = 0.2043
z* =
1. Let Z be a standard normal random variable. Find…
a. Pr (Z ≥ -0.78) b. Pr(-0.82 Z 1.31)
2. A random variable X is normally distributed with mean ? = 25.5
and standard deviation ? .0= 3.25.
Find Pr(23.03 ≤ ?? ≤ 29.14)
3. The math SAT is scaled so that the mean score is 500 and the
standard deviation is 100.
Assuming scores are normally distributed, find the probability that
a randomly selected student
scores
a....
Let z denote a random variable having a normal
distribution with μ = 0 and σ = 1. Determine each of the
probabilities below. (Round all answers to four decimal
places.)
(a) P(z < 0.2) =
(b) P(z < -0.2) =
(c) P(0.40 < z < 0.86) =
(d) P(-0.86 < z < -0.40)
=
(e) P(-0.40 < z < 0.86) =
(f) P(z > -1.24) =
(g) P(z < -1.5 or z > 2.50) =
Let z denote a random variable having a normal
distribution with μ = 0 and σ = 1. Determine each
of the following probabilities. (Round all answers to four decimal
places.)
(a)
P(z < 0.1) =
(b)
P(z < −0.1) =
(c)
P(0.40 < z < 0.85)
=
(d)
P(−0.85 < z < −0.40)
=
(e)
P(−0.40 < z < 0.85)
=
(f)
P(z > −1.25) =
(g)
P(z < −1.5 or
z > 2.50) =
Let z denote a...
Let z be a random variable with a standard normal
distribution.
Find “a” such that P(|Z| <A)= 0.95
This is what I have:
P(-A<Z<A) = 0.95
-A = -1.96
How do I use the symmetric property of normal distribution to make
A = 1.96?
My answer at the moment is P(|z|< (-1.96) = 0.95
Let z be a random variable with a standard normal distribution.
Find P(0 ≤ z ≤ 0.46), and shade the corresponding area under the
standard normal curve. (Use 4 decimal places.)
Let the random variable Z follow a standard normal distribution,
and let Z1 be a possible value of Z that is representing the 90th
percentile of the standard normal distribution. Find the value of
Z1.
Question 3 options:
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Let Z denote a standard normal random variable. Find the
probability P(Z < 0.81)? The area to the LEFT of 0.81?
----------------------------------------
Enter in format X.XX rounding UP so one-half
(1/2) is 0.50 and two-thirds (2/3) is 0.67 with rounding. Enter
-1.376 as -1.38 with rounding. NOTE: DO NOT ENTER
A PERCENTAGE (%).
|
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Let Z denote a standard normal random variable. Find the
probability P(Z > -1.29)? The area to the RIGHT of...
a) Let z be a random variable with a standard normal
distribution. Find the indicated probability. (Round your answer to
four decimal places.)
P(−2.02 ≤ z ≤ −0.31) =
Shade the corresponding area under the standard normal
curve.
b) Assume that x has a normal distribution with the
specified mean and standard deviation. Find the indicated
probability. (Round your answer to four decimal places.)
μ = 50; σ = 15
P(40 ≤ x ≤ 47) =
c) Find z such...