A sample is analyzed to determine its iron content Fe2+ via a redox titration with potassium chromate as the titrant. In the titration Fe2+ is oxidized to Fe3+ and CrO4 2- is reduced to Cr 3+. What is the percent by mass of iron in the sample if 0.9087g of the sample required 45.68mL of a 0.04322 M K2CrO4 solution to reach the endpoint?
I worked out the balanced equation to be:
8H+ + 3Fe2+ + CrO4 2- = 3Fe3+ + Cr3+ + 4H2O
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What is the mechanism by which solute is dissolved in non polar solvents? Explain briefly. (5 mark)
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Part B What mass of carbon dioxide is produced from the complete combustion of 6.90×10−3 g of methane? Express your answer with the appropriate units.
Part C What mass of water is produced from the complete combustion of 6.90×10−3 g of methane? Express your answer with the appropriate units. Part D What mass of oxygen is needed for the complete combustion of 6.90×10−3 g of methane? Express your answer with the appropriate units
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The equilibrium constant for the reaction of fluorine gas with bromine gas at 300 K is 54.7 and the reaction is: Br2(g) + F2(g) ⇔ 2 BrF(g) What is the equilibrium concentration of fluorine if the initial concentrations of bromine and fluorine were 0.121 moles/liter in a sealed container and no product was present initially?
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In each pair, indicate which substance has the stronger intermolecular forces and explain your reasoning: (a) Ne, Ar; (b) NF3, BF3; (c) SiH4, GeH4; (d) NaF, HF.
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1. Calculate the dilution factor and final concentration of the following target analytes:
20 mL of target analyte (2.5 M), to a final volume of 100 mL
2 mL of target analyte (3.23 ppm), to a final volume of 0.05 L.
5 mL of target analyte (15.9032 %), to a final volume of 1 dL.
1 dL of target analyte (4.0989 M), to a final volume of 0.25 L
0.025 L of target analyte (1.8982 g / L), to 79 g of ethanol.
10 mL of target analyte (2.0902 g / L), to 66.5 g of dichloromethane.
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A solution containing a mixture of metal cations was treated with dilute HCl and a precipitate formed. The solution was filtered and H2S was bubbled through the acidic solution. A precipitate again formed and was filtered off. Then, the pH was raised to about 8 and H2S was again bubbled through the solution. This time, no precipitate formed. Finally, the solution was treated with a sodium carbonate solution, which resulted in formation of a precipitate. Which metal ions were definitely present, which were definitely absent, and which may or may not have been present in the original mixture? Ag+, Zn2+, Co2+, Li+, Cu2+, Ca2+, Fe2+, Sn2+, Mg2+, Hg22+ Sb3+, Hg2+, Pb2+
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Please explain...
In the titration of a weak acid HA with 0.100 M NaOH, the stoichiometric point is known to occur at a pH value of approximately 11. Which of the following indicators would be best to use to mark the endpoint of this titration?
a. an indicator with Ka = 10–13
b. an indicator with Ka = 10–14
c. an indicator with Ka = 10–10
d. an indicator with Ka = 10–8
e. an indicator with Ka = 10–11
An indicator HIn has Ka = 1 × 10–8. At pH = 6.0, what is the ratio HIn/In– ?
a. 1/100
b. 10/1
c. 1/1
d. 100/1
e. none of these
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balance redox reaction that occurs in acidic conditions. what are coefficients for H + & Fe3+ once reaction is balanced? write it as H+=#; Fe +3 = #
Fe2+(aq)+Mn04-(aq) -> Fe3+(aq)+Mn2+(aq)
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1. Ph of H3O+ of 5.7x10^3
2. Ph of a 1.5x10^-2 m for HBr
3. ph of 3.24x10^-4 m of hypochlorous acid ka2.9x10^-8
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In organic chemistry, we have ortho/para activators and deactivators. Why do we not have meta activators?
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Indicate the concentration of each ion present in the solution formed by mixing the following. (Assume that the volumes are additive.)
(a) 40 mL of 0.100 M HCl and 10.0 mL of 0.600
M HCl
H+ ________ M
Cl - ________ M
(b) 15.0 mL of 0.300 M Na2SO4 and
20.6 mL of 0.200 M KCl
Na+ _________ M
K+ __________ M
SO42- __________ M
Cl - __________ M
(c) 3.50 g of NaCl in 40.6 mL of 0.365 M CaCl2
solution
Na+ ___________ M
Ca2+ __________ M
Cl - __________ M
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Calculate the hydronium ion concentration and the pH when 65.0 mL of 0.45 M NH3 is mixed with 65.0 mL of 0.45 M HCl (Ka = 5.6x10^-10).
Concentration =
pH=
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