Question

In: Physics

A car can decelerate at -3.25 m/s2 without skidding when coming to rest on a level...

A car can decelerate at -3.25 m/s2 without skidding when coming to rest on a level road.

What would its deceleration be if the road is inclined at 9.2 ∘ and the car moves uphill? Assume the same static friction coefficient.

Expert Solution

the data given

Deceleration of the car = -3.80 m/s²

Acceleration due to gravity = 9.8 m/s²

ehen car moves on straight path

frictional force experienced by the car is f = µN

where µ =frictional force constant

N = normal force

force on car due to its mass and acceleration = m a

where m= mass and a =Acceleration due to gravity = 9.8 m/s²

N =mg

mg =ma

₌a/g =3.25/9.8 =0.3316

when car moves upside

frictional force +mgsin =ma_new

mgcos +mgsin= -ma_new

gcos +gsin= -a_new

0.3316x9.8xcos9.2+9.8xsin9.2=-a_new

deceleration car goes up a_new=4.7747m/s2

genius_generous answered 2 years ago

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