In: Physics
a. Calculate the linear acceleration (in m/s2) of a car, the 0.340 m radius tires of which have an angular acceleration of 11.0 rad/s2. Assume no slippage.
b. How many revolutions do the tires make in 2.50 s if they start from rest?
c. What is their final angular velocity (in rad/s)?
d. What is the final velocity (in m/s) of the car?
a.
Linear acceleration or tangential acceleration = a_t = Angular
acceleration () * radius
(r)
a_t = * r = 11 * 0.34
= 3.74 m/s^2
b.
Let t = 2.5s be time taken
Formula :- = t +
1/2 t^2
Angle rotated ( ) = 0.t + 1/2 *
* t^2 = 1/2 * 11
* 2.5^2 = 34.375 rad
2 rad = 1
revolution
34.375 rad = 1/ 2 * 34.375 rev =
54
So , number of revolutions = 54
c.
Final angular velocity
= 0 + 11* 2.5
= 27.5 rad/s
d.
= 27.5 rad/s * 0.34 m = 9.35 m/s