In: Physics
A white billiard ball with mass mw = 1.33 kg is moving directly to the right with a speed of v = 2.96 m/s and collides elastically with a black billiard ball with the same mass mb = 1.33 kg that is initially at rest. The two collide elastically and the white ball ends up moving at an angle above the horizontal of ?w = 29
mw = mass of white ball = 1.33 kg
mb = mass of black ball = 1.33 kg
Vwix = velocity of white ball before collision along X-direction = 2.96 m/s
Vwiy = velocity of white ball before collision along Y-direction = 0 m/s
Vbix = velocity of blaack ball before collision along X-direction = 0 m/s
Vbiy = velocity of blaack ball before collision along Y-direction = 0 m/s
Vwf = velocity of white ball after collision
Vwfx = velocity of white ball after collision in X-direction = Vwf cos29
Vwfy = velocity of white ball after collision in Y-direction = Vwf Sin29
Vbf = velocity of black ball after collision
Vbfx = velocity of black ball after collision in X-direction = Vbf cos61
Vbfy = velocity of black ball after collision in Y-direction = -Vbf Sin61 (since it is along negative y-direction)
Using conservation of momentum along X-direction ::
mwVwix+ mbVbix= mw Vwfx + mbVbfx
inserting the values
2.96 + 0 = Vwf cos29 + Vbf cos61
Vwf (0.875) + Vbf (0.485) = 2.96 eq-1
Using conservation of momentum along Y-direction ::
mwVwiy+ mbVbiy= mw Vwfy + mbVbfy
inserting the values
0 + 0 = Vwf Sin29 -Vbf Sin61
Vwf Sin29 = Vbf Sin61
Vwf = 1.804 Vbf eq-2
Using eq-1 and eq-2
(1.804 Vbf ) (0.875) + Vbf (0.485) = 2.96
Vbf = 1.4345 m/s --------------------final speed of black ball
Vwf = 1.804 Vbf = 1.804 x 1.4345
Vwf = 2.588 m/s ----------------------- final speed of white ball
final total momentum = initial total momentum = mw Vwi= 1.33 x 2.96 = 3.937 kgm/s
final total energy = (0.5) mw V2wf + (0.5) mb V2bf = (0.5) (1.33) (2.5882 + 1.43452)
Final total energy = 5.822 J