In: Statistics and Probability
A study of the effect of television commercials on 12-year-old children measured their attention span, in seconds. The commercials were for clothes, food, and toys.
Clothes | Food | Toys |
34 | 38 | 64 |
30 | 34 | 50 |
44 | 51 | 39 |
35 | 42 | 48 |
28 | 47 | 63 |
31 | 42 | 53 |
17 | 34 | 48 |
31 | 43 | 58 |
20 | 57 | 47 |
47 | 51 | |
44 | 51 | |
54 | ||
1)Is there a difference in the mean attention span of the children for the various commercials?
The hypothesis of identical means can definitely be rejected/not rejected.There is a difference/no difference in the mean attention span
2)Are there significant differences between pairs of means?
Clothes have a mean attention span of at least ten minutes above/below the other groups
Answer: A study of the effect of television commercials on 12-year-old children measured their attention span, in seconds. The commercials were for clothes, food, and toys
Solution:
1) From the given data:
Group | n | Σx | mean | Σx^2 | Std.Dev |
Clothes | 9 | 270 | 30 | 8612 | 8 |
Food | 12 | 533 | 44.4167 | 24253 | 7.2546 |
Toys | 11 | 572 | 52 | 30278 | 7.3075 |
Total | 32 | 1375 | 42.969 | 63143 | 11.4455 |
Anova table:
Source | df | SS | MS | F | P-VALUE |
Factor | 2 | 2436.0521 | 1218.026 | 21.7382 | 0.00001 |
Error | 29 | 1624.9167 | 56.0316 | ||
Total | 3 | 4060.9688 |
The hypothesis test:
Null hypothesis, Ho: μ1 = μ2 = μ3
Alternative hypothesis, Ha: at least one of the μ is not equal.
From the ANOVA results:
F test statistic = 21.7382
P-value = 0.00001
Assuming significance level α = 0.05
Since P-value < α (0.05) significance level.
We reject the null hypothesis, Ho.
The hypothesis of identical means can definitely be rejected. There is difference in the mean attention span.
2)
Clothes have a mean attention span of at least ten minutes below the other groups.
If any doubt feel free to ask. If this answer is helpful to you then please upvote.