In: Statistics and Probability
A study of the effect of television commercials on 12-year-old children measured their attention span, in seconds. The commercials were for clothes, food, and toys.
Clothes | Food | Toys |
26 | 45 | 60 |
21 | 48 | 51 |
43 | 43 | 43 |
35 | 53 | 54 |
28 | 47 | 63 |
31 | 42 | 53 |
17 | 34 | 48 |
31 | 43 | 58 |
20 | 57 | 47 |
47 | 51 | |
44 | 51 | |
54 | ||
Complete the ANOVA table. Use 0.05 significance level. (Round the SS and MS values to 1 decimal place, and F value to 2 decimal places. Leave no cells blank — be certain to enter "0" wherever required. Round the df values to nearest whole number.)
Find the values of mean and standard deviation. (Round the mean and standard deviation values to 3 decimal places.)
Is there a difference in the mean attention span of the children for the various commercials?
Are there significant differences between pairs of means?
Run Anova single factor analysis in excel to answer the above questions
Go to data tab --> choose data analysis --> Anova single factor
Complete the ANOVA table. Use 0.05 significance level. (Round the SS and MS values to 1 decimal place, and F value to 2 decimal places. Leave no cells blank — be certain to enter "0" wherever required. Round the df values to nearest whole number.
ANOVA | ||||
Source of Variation | SS | df | MS | F |
Between Groups | 3182.0 | 2 | 1591.0 | 35.56 |
Within Groups | 1297.5 | 29 | 44.7 | |
Total | 4479.5 | 31 |
Find the values of mean and standard deviation. (Round the mean and standard deviation values to 3 decimal places.)
SUMMARY | |||||
Groups | Count | Sum | Average | Variance | Standard deviation |
Clothes | 9 | 252 | 28.000 | 66.25 | 8.139 |
Food | 12 | 557 | 46.417 | 38.27 | 6.186 |
Toys | 11 | 579 | 52.636 | 34.65 | 5.887 |
The square root of the variance is called the Standard Deviation σ.
Is there a difference in the mean attention span of the children for the various commercials? Are there significant differences between pairs of means?
p-value is less than 0.05
If the p-value is less than 0.05, we reject the null hypothesis that there's no difference between the means and conclude that a significant difference does exist