Question

In: Economics

1. A single firm produces widgets, with a cost function and inverse demand function as follows,...

1. A single firm produces widgets, with a cost function and inverse demand function as follows, C(q) = 150 + 2q P(Qd) = 10 ? 0.08Qd (a) Calculate the monopolist’s profit-maximizing price, quantity, and profit if he can charge a single price in the market (single price monopolist). (b) Suppose the firm can sell units after your answer to (a) at a lower price (2nd-degree price discrimination, timed-release). What quantity will be sold for what price in this second-tier market? Calculate the monopolist’s profit. (c) Suppose each new tier of pricing the monopolist introduces increases fixed costs by $2 (quantities can be irrational). What is the profit-maximizing quantity, number of prices, monopolist’s profit, and deadweight loss? (d) Suppose the firm can perfectly price discriminate (1st-degree) with a 40% increase in marginal cost; calculate the profit-maximizing quantity, monopolist’s profit, and deadweight loss? (e) Between (c) and (d), which is socially preferred? Which would the monopolist choose to do?

Solutions

Expert Solution

a) Under monopoly, equilibrium is attained where MR = MC

TR = P.Q = (10 - 0.08Q)Q = 10Q - 0.08Q2

MR = 10 - 0.16Q

TC = 150 + 2Q

MC = 2

It implies, MR = MC

10 - 0.16Q = 2

0.16Q = 8

Q = 800/16 = 100/2

Q = 50 units

P = 10 - 0.08(50) = 10 - 4 = $ 6

Profit = TR - TC = P.Q - (150 + 2X50) = 6 X 50 - 150 - 100 = 300 - 250 = $ 50

b) When monopoly firm perfectly price discriminate then equilibrium is where Demand = MC

P = MC

10 - 0.08Q = 2

8 = 0.08Q

Q = 800/8

Q = 100 units

P = 10 - 0.08(100) = $ 2

Monopolist profit = 2 X 100 = $ 200

c) Two-Part Pricing:

TR = P.Q = (10 - 0.08Q)Q = 10Q - 0.08Q2

MR = 10 - 0.16Q

TC = 150 + 2Q

MC = 2

It implies, MR = MC

10 - 0.16Q = 2

0.16Q = 8

Q = 800/16 = 100/2

Q = 50 units

P = 10 - 0.08(50) = 10 - 4 = $ 6

Entry fee = Area of shaded region = 1/2 X 50 X (10 - 6) = 25 X 4 = $ 100

Profit = 2 Entry Fee + (P - MC)Q = 2(100) + (6 - 2)50 = 200 + 200 = $ 400


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