In: Economics
A single firm produces widgets, with a cost function and inverse demand function as follows, C(q) = 150+2q P(Qd) = 10−0.08Qd
(a) Calculate the monopolist’s profit-maximizing price, quantity, and profit if he can charge a single price in the market (single price monopolist).
(b) Suppose the firm wants sell units after your answer to (a) at a lower price in a later time period (2nd-degree price discrimination). What quantity will be sold for what price in this second-tier market? Calculate the monopolist’s profit.
(c) Suppose the firm can perfectly price discriminate; calculate the monopolist’s profit.
a.
Single price:
In this case the stage of profit-maximizing is (MR = MC).
P = 10 – 0.08q ……. (price function)
TR = P × q = 10q – 0.08q^2
MR = Derivatives of TR with respect to q.
= 10q^(1 – 1) – (0.08 × 2)q^(2 – 1)
= 10q^0 – 0.16q
= 10 – 0.16q
Now given, TC = 150 + 2q
MC = Derivatives of TC with respect to q
= 0 + 2q^(1 – 1)
= 2q^0
= 2
For quantity:
MR = MC
10 – 0.16q = 2
10 – 2 = 0.16q
8 = 0.16q
8/0.16 = q
q = 50
For price:
By putting the value of q in the price function.
P = 10 – 0.08q ……. (price function)
= 10 – 0.08 × 50
= 10 – 4
= 6
For profit:
Profit = TR – TC
= [10q – 0.08q^2] – [150 + 2q]
= [10 × 50 – 0.08 × 50^2] – [150 + 2 × 50]
= [500 – 200] – [150 + 100]
= 300 – 250
= 50
Answers:
Price = 6
Quantity = 50
Profit = 50
b.
2nd degree price discrimination:
Given, lower price is in the later time. This could only be avail if there is (P = MC).
For price:
P = MC = 2
For quantity:
By putting the value of P in the price function.
P = 10 – 0.08q ……. (price function)
2 = 10 – 0.08q
2 – 10 = - 0.08q
-8 = - 0.08q
8/0.08 = q
q = 100
For profit:
Profit = TR – TC
= [10q – 0.08q^2] – [150 + 2q]
= [10 × 100 – 0.08 × 100^2] – [150 + 2 × 100]
= [1,000 – 800] – [150 + 200]
= 200 – 350
= -150
Answers:
Price = 2
Quantity = 100
Profit = -150
c.
Perfectly price discrimination:
Consumer surplus (CS) in case of “single price” method should be calculated first, where (P = 6; q = 50)
P = 10 – 0.08q ……. (price function)
If (q = 0), P = 10 – 0.08 × 0 = 10.
Therefore, CS = 0.5 × Difference in price × Difference in quantity
= 0.5 × (10 – 6) × (50 – 0)
= 0.5 × 4 × 50
= 100
Note: 0.5 is the part of formula.
Profit = Profit at “single price” system + CS
= 50 + 100
= 150 (Answer)
This is so because a price discriminating firm will capture all the CS.