In: Statistics and Probability
29)
Random samples of four different models of cars were selected and the gas mileage of each car was measured. The results are shown below.
Model A / Model B / Model C / Model D 26 / 27 / 20 / 28 30 / 23 / 25 / 27 25 / 26 / 25 / 21 25 / 22 / 26 / 26
Test the claim that the four different models have the same population mean. Use a significance level of 0.05. Use the p-value method of hypothesis testing.
Given:
Random samples of four different models of cars were selected and the gas mileage of each car was measured.
Data summary:
Groups | count , N | Sum | Average | Std. Dev |
Group 1 | 4 | 101 | 25.25 | 3.594 |
Group 2 | 4 | 105 | 26.25 | 2.9861 |
Group 3 | 4 | 97 | 24.25 | 2.2174 |
Group 4 | 4 | 99 | 24.75 | 1.893 |
ANOVA TABLE:
Source | df | SS | MS | F | P-value |
Between groups | 3 | 8.75 | 2.9167 | 0.3846 | 0.7661 |
Within groups | 12 | 91.0018 | 7.5835 | ||
Total | 15 | 99.7518 |
Hypothesis test:
The null and alternative hypothesis is
H0 : 1 = 2 = 3 = 4
Ha : At least two of means 1, 2, 3, 4 are not equal.
From the ANOVA table
P-value = 0.7661
Significance level, = 0.05
Since P-value is a greater than significance level 0.05, we fail to reject null hypothesis.
Conclusion: Faill to reject H0. There is insufficient evidence to conclude that the four different models have the same population mean.