In: Physics
Play with Pendulum Lab to figure out what variables affect the motion of a pendulum and write qualitative descriptions for each variable.
Design experiments to find the best equation for the relationship for length and period. Include a spreadsheet and chart with a trend line from Excel.
Based on your understanding from the Curve Fitting activity, discuss how well you think the equation really describes the relationship.
Design experiments to find the best equation for the relationship for initial angle and period. Include a spreadsheet and chart with a trend line from Excel.
Based on your understanding from the Curve Fitting activity, discuss how well you think the equation really describes the relationship.
Q1:
l(length) | "l^(1/2)" | T(time period) |
0.5 | 0.707106781 | 1.4186 |
0.75 | 0.866025404 | 1.7379 |
1 | 1 | 2.0068 |
1.25 | 1.118033989 | 2.2437 |
1.5 | 1.224744871 | 2.4579 |
1.75 | 1.322875656 | 2.6549 |
2 | 1.414213562 | 2.8381 |
2.25 | 1.5 | 3.0104 |
2.5 | 1.58113883 | 3.1732 |
Chart with trend line:
Q2:
T = 2*pi((l/g)^1/2)
We can clearly see that this equation is perfectly fine for small angle like 5 degree from above shown trend line.
Q3:
Case 2: | ||
for same length = 1 m and different angles | ||
Angle(degree) | T(time period) | |
1 | 2.0059 | |
2 | 2.006 | |
3 | 2.0062 | |
4 | 2.0064 | |
5 | 2.0068 | |
6 | 2.0072 | |
8 | 2.0083 | |
10 | 2.0097 | |
13 | 2.0123 | |
18 | 2.0183 | |
23 | 2.0262 | |
30 | 2.0408 | |
40 | 2.0687 |
Chart:
Q4:
we can clealy see that
T = 2*pi((l/g)^1/2)
does not hold perfectly for large angle. as we increase the initial angle of release time period also increases. from the formula given above no dependence of timeperiod over angle was expected but practicaly that is not true. time period also depends on initial angle of release