Question

In: Statistics and Probability

Please give a detailed explanation how to solve this with excel 1)This problem demonstrates a possible...

Please give a detailed explanation how to solve this with excel

1)This problem demonstrates a possible (though rare) situation that can occur with group comparisons. The groups are sections and the dependent variable is an exams score.

Section 1 Section 2 Section 3
84.9 58.5 74.1
70.6 57.6 81.5
76.4 65.8 74.9
62.5 84.1 79
81.2 80.5 72.3
67.5 44.4 65.8
75.5 68.6 71
68.6 41.8 67.8
79.2 64.8 75.5



Run a one-way ANOVA (fixed effect) with α=0.05α=0.05. Round the F-ratio to three decimal places and the p-value to four decimal places. Assume all population and ANOVA requirements are met.

F=
p=

2. Recent research indicates that the effectiveness of antidepressant medication is directly related to the severity of the depression (Khan, Brodhead, Kolts & Brown, 2005). Based on pretreatment depression scores, patients were divided into four groups based on their level of depression. After receiving the antidepressant medication, depression scores were measured again and the amount of improvement was recorded for each patient. The following data are similar to the results of the study.

Low
Moderate
High
Moderate
Moderately
Severe

Severe
1.5 3.9 3.6 2.8
1.7 2.3 3.6 4.9
0.2 0.5 2.4 2.3
2 3.1 3.1 3.3
1.1 3.5 2.3 4
0 3 2.5 3.8



From this table, conduct an one-way ANOVA. Calculate the F-ratio and p-value. Be sure to round your answers to three decimal places. Assume all population and ANOVA requirements are met.

F-ratio:  
p-value:  



What is your final conclusion? Use a significance level of α=0.02

  • There is not enough evidence to determine a difference between the treatments.
  • There is sufficient evidence that there exists a significant difference between treatments.

Solutions

Expert Solution

Answer(1):

We have to test:

H0: there is no difference in scores of three sections

H1: there is significant difference in scores of at least two sections

In Excel we can run a one-way ANOVA as below:

Paste the data in excel > go to Data tab > go to data analysis tool pack > select the “ANOVA: Single Factor” > select the data > click ok

The output of the excel ANOVA is as below:

Anova: Single Factor

SUMMARY

Groups

Count

Sum

Average

Variance

Section 1

9

666.4

74.044

52.613

Section 2

9

566.1

62.900

204.827

Section 3

9

661.9

73.544

25.003

ANOVA

Source of Variation

SS

df

MS

F

P-value

F crit

Between Groups

713.259

2

356.629

3.788

0.0372

3.403

Within Groups

2259.544

24

94.148

Total

2972.803

26

F=3.788

p=0.0372

We can observe that the p-value is less than α=0.05 which indicates that we have enough evidence against null hypothesis to reject it at 0.05 level, so we to reject the null hypothesis and we can conclude that there is significant difference in scores of at least two sections.

The Screen shot of Excel steps is as below:

Answer(2):

Answer(2):

We have to test:

H0: There is no difference in between treatments

H1: There is significant difference between treatments

In Excel we can run a one-way ANOVA as below:

Paste the data in excel > go to Data tab > go to data analysis tool pack > select the “ANOVA: Single Factor” > select the data > click ok

The output of the excel ANOVA is as below:

Anova: Single Factor

SUMMARY

Groups

Count

Sum

Average

Variance

Low Moderate

6

6.5

1.083

0.670

High Moderate

6

16.3

2.717

1.466

Moderately Severe

6

17.5

2.917

0.358

Severe

6

21.1

3.517

0.854

ANOVA

Source of Variation

SS

Df

MS

F

P-value

F crit

Between Groups

19.485

3

6.495

7.763

0.001

3.098

Within Groups

16.733

20

0.837

Total

36.218

23

F-ratio: 7.763

p-value: 0.001

We can observe that the p-value is less than α=0.02 which indicates that we have strong evidence against null hypothesis to reject it at 0.02 level, so we reject the null hypothesis and we can conclude that there is significant difference Between the treatments.

The Screen shot of Excel steps is as below:


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