In: Statistics and Probability
Please give a detailed explanation how to solve this with excel
1)This problem demonstrates a possible (though rare) situation that can occur with group comparisons. The groups are sections and the dependent variable is an exams score.
Section 1 | Section 2 | Section 3 |
---|---|---|
84.9 | 58.5 | 74.1 |
70.6 | 57.6 | 81.5 |
76.4 | 65.8 | 74.9 |
62.5 | 84.1 | 79 |
81.2 | 80.5 | 72.3 |
67.5 | 44.4 | 65.8 |
75.5 | 68.6 | 71 |
68.6 | 41.8 | 67.8 |
79.2 | 64.8 | 75.5 |
Run a one-way ANOVA (fixed effect) with α=0.05α=0.05. Round the
F-ratio to three decimal places and the p-value to four
decimal places. Assume all population and ANOVA requirements are
met.
F=
p=
2. Recent research indicates that the effectiveness of
antidepressant medication is directly related to the severity of
the depression (Khan, Brodhead, Kolts & Brown, 2005). Based on
pretreatment depression scores, patients were divided into four
groups based on their level of depression. After receiving the
antidepressant medication, depression scores were measured again
and the amount of improvement was recorded for each patient. The
following data are similar to the results of the study.
Low Moderate |
High Moderate |
Moderately Severe |
Severe |
---|---|---|---|
1.5 | 3.9 | 3.6 | 2.8 |
1.7 | 2.3 | 3.6 | 4.9 |
0.2 | 0.5 | 2.4 | 2.3 |
2 | 3.1 | 3.1 | 3.3 |
1.1 | 3.5 | 2.3 | 4 |
0 | 3 | 2.5 | 3.8 |
From this table, conduct an one-way ANOVA. Calculate the F-ratio
and p-value. Be sure to round your answers to three decimal
places. Assume all population and ANOVA requirements are
met.
F-ratio:
p-value:
What is your final conclusion? Use a significance level of
α=0.02
Answer(1):
We have to test:
H0: there is no difference in scores of three sections
H1: there is significant difference in scores of at least two sections
In Excel we can run a one-way ANOVA as below:
Paste the data in excel > go to Data tab > go to data analysis tool pack > select the “ANOVA: Single Factor” > select the data > click ok
The output of the excel ANOVA is as below:
Anova: Single Factor |
||||||
SUMMARY |
||||||
Groups |
Count |
Sum |
Average |
Variance |
||
Section 1 |
9 |
666.4 |
74.044 |
52.613 |
||
Section 2 |
9 |
566.1 |
62.900 |
204.827 |
||
Section 3 |
9 |
661.9 |
73.544 |
25.003 |
||
ANOVA |
||||||
Source of Variation |
SS |
df |
MS |
F |
P-value |
F crit |
Between Groups |
713.259 |
2 |
356.629 |
3.788 |
0.0372 |
3.403 |
Within Groups |
2259.544 |
24 |
94.148 |
|||
Total |
2972.803 |
26 |
F=3.788
p=0.0372
We can observe that the p-value is less than α=0.05 which indicates that we have enough evidence against null hypothesis to reject it at 0.05 level, so we to reject the null hypothesis and we can conclude that there is significant difference in scores of at least two sections.
The Screen shot of Excel steps is as below:
Answer(2):
Answer(2):
We have to test:
H0: There is no difference in between treatments
H1: There is significant difference between treatments
In Excel we can run a one-way ANOVA as below:
Paste the data in excel > go to Data tab > go to data analysis tool pack > select the “ANOVA: Single Factor” > select the data > click ok
The output of the excel ANOVA is as below:
Anova: Single Factor |
||||||
SUMMARY |
||||||
Groups |
Count |
Sum |
Average |
Variance |
||
Low Moderate |
6 |
6.5 |
1.083 |
0.670 |
||
High Moderate |
6 |
16.3 |
2.717 |
1.466 |
||
Moderately Severe |
6 |
17.5 |
2.917 |
0.358 |
||
Severe |
6 |
21.1 |
3.517 |
0.854 |
||
ANOVA |
||||||
Source of Variation |
SS |
Df |
MS |
F |
P-value |
F crit |
Between Groups |
19.485 |
3 |
6.495 |
7.763 |
0.001 |
3.098 |
Within Groups |
16.733 |
20 |
0.837 |
|||
Total |
36.218 |
23 |
F-ratio: 7.763
p-value: 0.001
We can observe that the p-value is less than α=0.02 which indicates that we have strong evidence against null hypothesis to reject it at 0.02 level, so we reject the null hypothesis and we can conclude that there is significant difference Between the treatments.
The Screen shot of Excel steps is as below: