Question

In: Statistics and Probability

The mean and standard deviation of a random sample of n measurements are equal to 33.6...

The mean and standard deviation of a random sample of n measurements are equal to 33.6 and 3.5, respectively.

A) The 99% confidence interval for π if n = 49 is approximately ( ___ , ___ )

B) The 99% confidence interval π if n = 196 is approximately ( ___ , ___ )

Solutions

Expert Solution

The values provided in the above question are as below

= mean = 33.6

= standard drviation = 3.5

A) The 99% confidence interval for π if n = 49

Here = 0.01 then /2 = 0.005

Using normal probability table

Using all values in above formula

The 99% confidence interval for π if n = 49

The 99% confidence interval for π if n = 49 is approximately ( 32.31 , 34.89)

B) The 99% confidence interval for π if n = 196

Here = 0.01 then /2 = 0.005

Using normal probability table

Using all values in above formula

The 99% confidence interval for π if n = 196

The 99% confidence interval for π if n = 196 is approximately ( 32.955, 34.245)

Summary : -

A) The 99% confidence interval for π if n = 49 is approximately ( 32.31 , 34.89)

B) The 99% confidence interval for π if n = 196 is approximately ( 32.955, 34.245)


Related Solutions

The mean and standard deviation of a random sample of n measurements are equal to 33.2...
The mean and standard deviation of a random sample of n measurements are equal to 33.2 and 3.6?, respectively. a. Find a 90?% confidence interval for mu if nequals81. b. Find a 90?% confidence interval for mu if nequals324. c. Find the widths of the confidence intervals found in parts a and b. What is the effect on the width of a confidence interval of quadrupling the sample size while holding the confidence coefficient? fixed?
The mean and standard deviation of a random sample of n measurements are equal to 33.5...
The mean and standard deviation of a random sample of n measurements are equal to 33.5 and 3.5, respectively. a. Find a 90% confidence interval for m if n = 144. b. Find a 90% confidence interval for m if n = 576. c. Find the widths of the confidence intervals found in parts a and b. What is the effect on the width of a confidence interval of quadrupling the sample size while holding the confidence coefficient fixed?
A random sample of ?n measurements was selected from a population with standard deviation 13.913.9 and...
A random sample of ?n measurements was selected from a population with standard deviation 13.913.9 and unknown mean ?μ. Calculate a 9999 % confidence interval for ?μ for each of the following situations: (a) ?=35, ?⎯⎯⎯=104.9n=35, x¯=104.9 (b) ?=60, ?⎯⎯⎯=104.9n=60, x¯=104.9 (c) ?=85, ?⎯⎯⎯=104.9n=85, x¯=104.9 (d) In general, we can say that for the same confidence level, increasing the sample size  the margin of error (width) of the confidence interval. (Enter: ''DECREASES'', ''DOES NOT CHANGE'' or ''INCREASES'', without the quotes.)
A random sample of ?n measurements was selected from a population with standard deviation ?=14.6 and...
A random sample of ?n measurements was selected from a population with standard deviation ?=14.6 and unknown mean ?. Calculate a 99% confidence interval for ? for each of the following situations: (a) ?=45, ?⎯⎯⎯=76.3 ____ ≤?≤ _______ (b)  ?=65, ?⎯⎯⎯=76.3 ____  ≤?≤ ______ (c)  ?=85, ?⎯⎯⎯=76.3 ______ ≤?≤ _______
A random sample of ?n measurements was selected from a population with standard deviation ?=11.7 and...
A random sample of ?n measurements was selected from a population with standard deviation ?=11.7 and unknown mean ?. Calculate a 95% confidence interval for ? for each of the following situations: (a) ?=60, ?=85 ≤?≤ (b)  ?=75, ?=85 ≤?≤ (c)  ?=100, ?=85 ≤?≤
A random sample of n measurements was selected from a population with standard deviation σ=19.8 and...
A random sample of n measurements was selected from a population with standard deviation σ=19.8 and unknown mean μ. Calculate a 99 % confidence interval for μ for each of the following situations (I did the third one right but can't get these two to work so figured I'd ask before emailing my instructor): (a) n=65, x¯=96.7 90.36380962, 103.0361904 = wrong (b) n=80, x¯=96.7 90.989, 102.411 = wrong Am I wrong or is it the system lol?
A random sample of n measurements was selected from a population with standard deviation σ=13.6and unknown...
A random sample of n measurements was selected from a population with standard deviation σ=13.6and unknown mean μ. Calculate a 90 % confidence interval for μ for each of the following situations: (a) n=35, x=78.5 (b) n=50, x¯=78.5 (c)n=70, x¯=78.5
A simple random sample with n = 56 provided a sample mean of 26.5 and a sample standard deviation of 4.4.
  A simple random sample with n = 56 provided a sample mean of 26.5 and a sample standard deviation of 4.4. (Round your answers to one decimal place.) (a) Develop a 90% confidence interval for the population mean. to (b) Develop a 95% confidence interval for the population mean. to (c) Develop a 99% confidence interval for the population mean. to (d) What happens to the margin of error and the confidence interval as the confidence level is increased?...
A random sample of ? measurements was selected from a population with standard deviation ?=13.7 and...
A random sample of ? measurements was selected from a population with standard deviation ?=13.7 and unknown mean ?. Calculate a 99 % confidence interval for ? for each of the following situations: (a) n=55, x¯=100.4 ≤?≤ (b)  n=75, x¯=100.4 ≤?≤ (c)  n=105, x¯=100.4 ≤?≤
A random sample of ? measurements was selected from a population with standard deviation ?=16.6 and...
A random sample of ? measurements was selected from a population with standard deviation ?=16.6 and unknown mean ?. Calculate a 90 % confidence interval for ? for each of the following situations: (a) ?=65, ?⎯⎯⎯=86.1 (b) ?=80, ?⎯⎯⎯=86.1 (c) ?=100, ?⎯⎯⎯=86.1
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT