A random sample of n measurements was selected from a population with standard deviation σ=19.8 and...

A random sample of n measurements was selected from a population with standard deviation σ=19.8 and unknown mean μ. Calculate a 99 % confidence interval for μ for each of the following situations (I did the third one right but can't get these two to work so figured I'd ask before emailing my instructor):

(a) n=65, x¯=96.7

90.36380962, 103.0361904 = wrong

(b) n=80, x¯=96.7

90.989, 102.411 = wrong

Am I wrong or is it the system lol?

Expert Solution

Solution:

(a)

----------------------------------------------------------

(b)

orchestra answered 1 year ago

A random sample of n measurements was selected from a population with standard deviation σ=13.6and unknown...

A random sample of n measurements was selected from a population with standard deviation σ=13.6and unknown mean μ. Calculate a 90 % confidence interval for μ for each of the following situations: (a) n=35, x=78.5 (b) n=50, x¯=78.5 (c)n=70, x¯=78.5

A random sample of ? measurements was selected from a population with standard deviation σ=11.7 and...

A random sample of ? measurements was selected from a population with standard deviation σ=11.7 and unknown mean μ. Calculate a 90 % confidence interval for μ for each of the following situations: (a) ?=40, ?=72.1 ≤. μ ≤ (b) ?=60, ?=72.1 μ ≤ (c) ?=85, ?=72.1 ≤. μ. ≤

A random sample of ?n measurements was selected from a population with standard deviation 13.913.9 and...

A random sample of ?n measurements was selected from a population with standard deviation 13.913.9 and unknown mean ?μ. Calculate a 9999 % confidence interval for ?μ for each of the following situations: (a) ?=35, ?⎯⎯⎯=104.9n=35, x¯=104.9 (b) ?=60, ?⎯⎯⎯=104.9n=60, x¯=104.9 (c) ?=85, ?⎯⎯⎯=104.9n=85, x¯=104.9 (d) In general, we can say that for the same confidence level, increasing the sample size the margin of error (width) of the confidence interval. (Enter: ''DECREASES'', ''DOES NOT CHANGE'' or ''INCREASES'', without the quotes.)

A random sample of ?n measurements was selected from a population with standard deviation ?=14.6 and...

A random sample of ?n measurements was selected from a population with standard deviation ?=14.6 and unknown mean ?. Calculate a 99% confidence interval for ? for each of the following situations: (a) ?=45, ?⎯⎯⎯=76.3 ____ ≤?≤ _______ (b) ?=65, ?⎯⎯⎯=76.3 ____ ≤?≤ ______ (c) ?=85, ?⎯⎯⎯=76.3 ______ ≤?≤ _______

A random sample of ?n measurements was selected from a population with standard deviation ?=11.7 and...

A random sample of ?n measurements was selected from a population with standard deviation ?=11.7 and unknown mean ?. Calculate a 95% confidence interval for ? for each of the following situations: (a) ?=60, ?=85 ≤?≤ (b) ?=75, ?=85 ≤?≤ (c) ?=100, ?=85 ≤?≤

A random sample of n observations is selected from a population with standard deviation σ =...

A random sample of n observations is selected from a population with standard deviation σ = 1. Calculate the standard error of the mean (SE) for these values of n. (Round your answers to three decimal places.) (a) n = 1 SE = (b) n = 2 SE = (c) n = 4 SE = (d) n = 9 SE = (e) n = 16 SE = (f) n = 25 SE = (g) n = 100 SE =

A random sample of nn measurements was selected from a population with standard deviation σ=19.9σ=19.9 and...

A random sample of nn measurements was selected from a population with standard deviation σ=19.9σ=19.9 and unknown mean μμ. Calculate a 9595 % confidence interval for μμ for each of the following situations: (a) n=60, x¯¯¯=95.6n=60, x¯=95.6 ≤μ≤≤μ≤ (b) n=80, x¯¯¯=95.6n=80, x¯=95.6 ≤μ≤≤μ≤ (c) n=100, x¯¯¯=95.6n=100, x¯=95.6 ≤μ≤≤μ≤ (d) In general, we can say that for the same confidence level, increasing the sample size the margin of error (width) of the confidence interval. (Enter: ''DECREASES'', ''DOES NOT CHANGE'' or ''INCREASES'', without...

A random sample of ? measurements was selected from a population with standard deviation ?=13.7 and...

A random sample of ? measurements was selected from a population with standard deviation ?=13.7 and unknown mean ?. Calculate a 99 % confidence interval for ? for each of the following situations: (a) n=55, x¯=100.4 ≤?≤ (b) n=75, x¯=100.4 ≤?≤ (c) n=105, x¯=100.4 ≤?≤

A random sample of n1 = 49 measurements from a population with population standard deviation σ1...

A random sample of n1 = 49 measurements from a population with population standard deviation σ1 = 5 had a sample mean of x1 = 8. An independent random sample of n2 = 64 measurements from a second population with population standard deviation σ2 = 6 had a sample mean of x2 = 11. Test the claim that the population means are different. Use level of significance 0.01. (a) Check Requirements: What distribution does the sample test statistic follow? Explain....

A random sample of 49 measurements from a population with population standard deviation σ1 = 3...

A random sample of 49 measurements from a population with population standard deviation σ1 = 3 had a sample mean of x1 = 12. An independent random sample of 64 measurements from a second population with population standard deviation σ2 = 4 had a sample mean of x2 = 14. Test the claim that the population means are different. Use level of significance 0.01. (g) Find a 99% confidence interval for μ1 − μ2. (Round your answers to two decimal...

Question