In: Economics
Use an appropriate analysis technique of your choosing to evaluate the following three mutually exclusive projects each lasting 6 years. Which project should be selected if MARR = 6%.
Project 1 involves an initial cost of $300,000 and annual costs of $50,000. The project will generate annual revenues of $110,000. At the end of year 6, the project will have a salvage value of $25,000.
Project 2 will require an initial investment of $150,000 and annual costs of $25,000. There will be no revenues in years 1-3, but years 4-6 will have annual revenues of $150,000. There is no salvage value.
Project 3 also has an initial cost of $150,000. Annual costs are 75,000, and annual revenue in year 1 is $90,000, increasing by $10,000 each year through year 6. There is no salvage value.
Use an appropriate analysis technique of your choosing to evaluate the following three mutually exclusive projects each lasting 6 years. Which project should be selected if MARR = 6%. Project 1 involves an initial cost of $300,000 and annual costs of $50,000. The project will generate annual revenues of $110,000. At the end of year 6, the project will have a salvage value of $25,000. Project 2 will require an initial investment of $150,000 and annual costs of $25,000. There will be no revenues in years 1-3, but years 4-6 will have annual revenues of $150,000. There is no salvage value. Project 3 also has an initial cost of $150,000. Annual costs are 75,000, and annual revenue in year 1 is $90,000, increasing by $10,000 each year through year 6. There is no salvage value.
Since all projects have equal lives, we use PW method.
(a) Project 1
Annual net benefit (NAB) = Annual revenue - Annual cost
In year 6, Annual revenue = 110,000 + 25,000 = 135,000
PW is computed as follows.
PROJECT - 1 | |||||
Year | Revenue | Cost | NAB | PV Factor@6% | Discounted NAB |
0 | 3,00,000 | -3,00,000 | 1.0000 | -3,00,000 | |
1 | 1,10,000 | 50,000 | 60,000 | 0.9434 | 56,604 |
2 | 1,10,000 | 50,000 | 60,000 | 0.8900 | 53,400 |
3 | 1,10,000 | 50,000 | 60,000 | 0.8396 | 50,377 |
4 | 1,10,000 | 50,000 | 60,000 | 0.7921 | 47,526 |
5 | 1,10,000 | 50,000 | 60,000 | 0.7473 | 44,835 |
6 | 1,35,000 | 50,000 | 85,000 | 0.7050 | 59,922 |
PW of NAB ($) = | 12,663 |
(b) Project 2
Annual net benefit (NAB) = Annual revenue - Annual cost
PW is computed as follows.
PROJECT - 2 | |||||
Year | Revenue | Cost | NAB | PV Factor@6% | Discounted NAB |
0 | 1,50,000 | -1,50,000 | 1.0000 | -1,50,000 | |
1 | 0 | 25,000 | -25,000 | 0.9434 | -23,585 |
2 | 0 | 25,000 | -25,000 | 0.8900 | -22,250 |
3 | 0 | 25,000 | -25,000 | 0.8396 | -20,990 |
4 | 1,50,000 | 25,000 | 1,25,000 | 0.7921 | 99,012 |
5 | 1,50,000 | 25,000 | 1,25,000 | 0.7473 | 93,407 |
6 | 1,50,000 | 25,000 | 1,25,000 | 0.7050 | 88,120 |
PW of NAB ($) = | 63,714 |
(c) Project 3
Annual net benefit (NAB) = Annual revenue - Annual cost
PW is computed as follows.
PROJECT - 3 | |||||
Year | Revenue | Cost | NAB | PV Factor@6% | Discounted NAB |
0 | 1,50,000 | -1,50,000 | 1.0000 | -1,50,000 | |
1 | 90,000 | 75,000 | 15,000 | 0.9434 | 14,151 |
2 | 1,00,000 | 75,000 | 25,000 | 0.8900 | 22,250 |
3 | 1,10,000 | 75,000 | 35,000 | 0.8396 | 29,387 |
4 | 1,20,000 | 75,000 | 45,000 | 0.7921 | 35,644 |
5 | 1,30,000 | 75,000 | 55,000 | 0.7473 | 41,099 |
6 | 1,40,000 | 75,000 | 65,000 | 0.7050 | 45,822 |
PW of NAB ($) = | 38,353 |
(d) Decision:
Since Project 2 has highest PW, Project 2 is to be selected.