An electron in a television picture tube travels at 3 × 107 m/s.
Does the earth’s...
An electron in a television picture tube travels at 3 × 107 m/s.
Does the earth’s gravitational field or its magnetic
field exert the greater force on the electron? Assume v is
perpendicular to B.
An electron with a speed of 3.5 x 107 m/s travels upwards into a
3.0 T magnetic field directed into the page. After the particle is
deflect it enters a circular path. What direction is the particle
deflected? What is the radius of the circular path the electron
travels through? Include a diagram.
A 20.0 m long wire is carrying a 150.0 mA current parallel to a
second wire that is extremely long which carries a current of 250.0
mA...
An electron is slowed down quickly from 107 m/s to
0.5 * 107 m/s, and a single photon is created in the
process. Identify the radiation process (eg. Compton, positron
emission, etc.) and compute the frequency and wavelength of the
emitted photon.
An electron travels with speed 2.0 × 107 m/s between the two
parallel charged plates shown in the figure. The plates are
separated by a 100 V battery.
(a)What is the direction of the magnetic field to allow the
electron to pass between the plates without being deflected?
Explain how you determine the direction.
(b) What magnetic field strength will allow the electron to pass
between the plates without being deflected? SHOW FULL WORK
An electron with speed 2.75×107 m/s is traveling
parallel to a uniform electric field of magnitude
1.20×104 N/C .
How far will the electron travel before it stops?
How much time will elapse before it returns to its starting
point?
An electron in a TV camera tube is moving at 7.20×106
m/s in a magnetic field of strength 59 mT.
Without knowing the direction of the field, what can you say about
the greatest and least magnitude of the force acting on the
electron due to the field? Maximum force?
Minimum force?
At one point the acceleration of the electron is
6.327×1016 m/s2. What is the angle
between the electron velocity and the magnetic field? (deg)
An electron in a TV camera tube is moving at 6.20×106 m/s in a
magnetic field of strength 75 mT. Without knowing the direction of
the field, what can you say about the greatest and least magnitude
of the force acting on the electron due to the field? Maximum
force? Minimum force? At one point the acceleration of the electron
is 7.767×1016 m/s2. What is the angle between the electron velocity
and the magnetic field? (deg)
An electron experiences the greatest force as it travels
3.0×106 m/s in a magnetic field when it is moving
northward. The force is vertically upward and of magnitude
8.0×10−13 N .
What is the magnitude and direction of the magnetic field?
Part B
B⃗ has west direction.
B⃗ has east direction.
B⃗ has north direction.
B⃗ has south direction.
In a TV picture tube the accelerating voltage is 17.0 kV, and
the electron beam passes through an aperture 0.40 mm in diameter to
a screen 0.230 m away. What is the uncertainty in position of the
point where the electrons strike the screen?
if an electron travels 0.200 m from an electron gun to
a TV screen in 13.0 ns, what voltage ( inV) was used to accelerate
it? (Note that the voltage you obtain here is lower than actually
used in TVs to avoid the necessity of relativistic
corrections.)
The electron gun in a television tube uses a uniform electric
field to accelerate electrons from rest to 4.7×107 m/s
in a distance of 1.3 cm .
What is the electric field strength?