Two point charges are placed on the x axis as follows: Charge q1 = 4.00nC is...

Two point charges are placed on the x axis as follows: Charge q1 = 4.00nC is located at x = 0.200m , and charge q2 = 5.00nC is at x=?0.300m. What are the magnitude and direction of the net force exerted by these two charges on a negative point charge q3 = -0.600nC placed at the origin?

A. magnitude

B. direction

Expert Solution

The electrostatic force of attraction between the charge q1 and q3is
                     F₁₃ =(9.0*10⁹N.m²/C²)(4.0*10^-9C)(0.60*10^-9C)/ (0.20m)²
                            = 540nN
And the electrostatic force of attraction between the charge q2 andq3 is
                  F₂₃ =(9.0*10⁹N.m²/C²)(5.0*10^-9C)(0.60*10^-9C)/ (0.30m)²
                            = 300 nN
Now the net force acting on the charge q3 is
            F = F₁₃ - F₂₃
               = 540nN - 300nN
               = 240nN along positive x axis.

genius_generous answered 7 months ago

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