In: Statistics and Probability
Listed below are the lead concentrations in
muμg/g
measured in different traditional medicines. Use a
0.050.05
significance level to test the claim that the mean lead concentration for all such medicines is less than
1515
muμg/g.
Assume that the lead concentrations in traditional medicines are normally distributed
12
13
19.5
5.5
6.5
4
8.5
16
10
8.5
Determine the test statistic.
Determine the P-value.
State the final conclusion that addresses the original claim.
▼
Reject
Fail to reject
Upper H 0H0.
There is
▼
sufficient
not sufficient
evidence to conclude that the mean lead concentration for all such medicines is
▼
less than
equal to
greater than
not
1515
muμg/g.
the necessary calculation table:-
concentration (x) | x2 |
12 | 144 |
13 | 169 |
19.5 | 380.25 |
5.5 | 30.25 |
6.5 | 42.25 |
4 | 16 |
8.5 | 72.25 |
16 | 256 |
10 | 100 |
8.5 | 72.25 |
sum=103.5 | sum=1282.25 |
sample size (n) = 10
hypothesis:-
the test statistic be:-
degrees of freedom = (n-1) = (10-1) = 9
the p value is :-
[ in any blank cell of excel type =T.DIST(-3.0365,9,TRUE)]
decision:-
p value = 0.007 <0.05 (alpha)
reject the H0and There is sufficient evidence to conclude that the mean lead concentration for all such medicines is less than 15 mg/g.
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