Question

Listed below are the lead concentrations in mu g/g measured in different traditional medicines. Use a 0.01 significance level to test the claim that the mean lead concentration for all such medicines is less than 17 mu g/g. 17 4 22 11.5 14 19 4.5 2.5 4 22

What are the null and alternative hypotheses? A. Upper H 0 : muequals17 mu g/g Upper H 1 : muless than17 mu g/g B. Upper H 0 : muequals17 mu g/g Upper H 1 : mugreater than17 mu g/g C. Upper H 0 : mugreater than17 mu g/g Upper H 1 : muless than17 mu g/g D. Upper H 0 : muequals17 mu g/g Upper H 1 : munot equals17 mu g/g

Determine the test statistic.

__ (Round to two decimal places as needed.)

Determine the P-value.

____ (Round to three decimal places as needed.)

State the final conclusion that addresses the original claim. ▼ Reject or Fail to reject H 0. There is not sufficient or sufficient ▼ evidence to conclude that the mean lead concentration for all such medicines is not, equal to, less than or greater than▼ 17 mu g/g. Click to select your answer(s).

Answer 1

	Values ( X )
	17	24.5025
	4	64.8025
	22	99.0025
	11.5	0.3025
	14	3.8025
	19	48.3025
	4.5	57.0025
	2.5	91.2025
	4	64.8025
	22	99.0025
Total	120.5	552.725

Mean

Standard deviation

To Test :-

H0 :-  

H1 :-  

  Test Statistic :-


t = -1.9974   - 2.00

Test Criteria :-
Reject null hypothesis if


Result :- Fail to reject null hypothesis

Decision based on P value
P - value = P ( t > 1.9974 ) = 0.0384
Reject null hypothesis if P value < level of significance
P - value = 0.0384 > 0.01 ,hence we fail to reject null hypothesis
Conclusion :- Fail to reject null hypothesis

State the final conclusion that addresses the original claim. Fail to reject H 0. There is not sufficient evidence to conclude that the mean lead concentration for all such medicines is less than 17 mu g/g.