In: Statistics and Probability
A physician with a practice is currently serving 280patients. The physician would like to administer a survey to his patients to measure their satisfaction level with his practice. A random sample of
23patients had an average satisfaction score of 7.7on a scale of 1-10. The sample standard deviation was 1.7.
Construct a 99% confidence interval to estimate the average satisfaction score for the physician's practice.
The 99% confidence interval to estimate the average satisfaction score is
(___,___)
We have given sample mean is and the sample standard deviation is s = 1.7. The size of the sample is n = 23 and the required confidence level is
.The critical t-value for and df = 22 degrees of freedom is .
The 99% confidence for the population mean μ is
computed using the following expression
The 99% confidence interval to estimate the average satisfaction score is
(6.701,8.669)