In: Chemistry
1. A physician wishes to administer 1,700,000 units of penicillin G potassium every 4 hours. If 1 unit of penicillin G potassium (C16H17KN2O4S: m.w. 372) equals 0.8 mcg, how many milliequivalents of K+ will the patient receive in a 24-hour period?
2. How many millimoles of calcium gluconate (Ca(C6H11O7)2: m.w. 430) are represented in 10 mL of a 20% w/v calcium gluconate solution?
1.
Number of doses that are administered in 24 hour period = 24 /4 = 6 doses.
Total number of units in 6 doses = 6 * 1,700,000 units = 10200000 units.
Mass of penicillin G potassium1 unit = 0.8 mcg = 0.8 × 10–6 g
Total mass of penicillin G potassium = 10200000 units. * 0.8 × 10–6 g/1 unit = 8.16 g
Molecular weight of penicillin G potassium = 372 g/mol
Number of moles of penicillin G potassium = 8.16 g/(372 g/mol) = 0.021935 mol = 21.935 mmol
Number of milli-equivalents of K+ = 21.9 milli equivalents.
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2. We know that
Number of moles of calcium gluconate = mass/mol.wt. = 2 g/(430 g/mol) = 0.004651 mol = 4.651 mmol
Number of milli moles of Calcium Gluconate = 4.65 mmol