Question

In: Statistics and Probability

The Downtown Parking Authority of Tampa, Florida, reported the following information for a sample of 232...

The Downtown Parking Authority of Tampa, Florida, reported the following information for a sample of 232 customers on the number of hours cars are parked and the amount they are charged.

Number of Hours Frequency Amount Charged
1 20 $ 3
2 37 7
3 49 10
4 39 17
5 33 21
6 17 25
7 3 27
8 34 31
  
232
  
a.

Convert the information on the number of hours parked to a probability distribution. (Round your answers to 3 decimal places.)

  
  Hours Probability
1    
2    
3    
4    
5    
6    
7    
8    
a-2. Is this a discrete or a continuous probability distribution?
  
  • Continuous

  • Discrete

b-1.

Find the mean and the standard deviation of the number of hours parked. (Do not round intermediate calculations. Round your final answers to 3 decimal places.)

  
  
  Mean   
  Standard deviation   
b-2.

How long is a typical customer parked? (Do not round intermediate calculations. Round your final answers to 3 decimal places.)

  
  The typical customer is parked for hours
c.

Find the mean and the standard deviation of the amount charged. (Do not round intermediate calculations. Round your final answers to 3 decimal places.)

  
  
  Mean   
  Standard deviation   

Solutions

Expert Solution

a-1)

The probability is for each number of hour is obtained by dividing the frequency by total frequency,

Number of Hours Frequency Probability
1 20 20/232=0.086
2 37 37/232=0.159
3 49 49/232=0.211
4 39 39/232=0.168
5 33 33/232=0.142
6 17 17/232=0.073
7 3 3/232=0.013
8 34 34/232=0.147
Total 232

a-2)

Answer: discrete

Explanation: Since we calculating the probability for discrete data (frequency), this is a discrete probability distribution.

b-1)

The mean for the the number of hours parked is obtained using the formula,

Number of Hours, x Frequency, f
1 20 20
2 37 74
3 49 147
4 39 156
5 33 165
6 17 102
7 3 21
8 34 272
Total 232 957

The standard deviation for the number of hours parked is obtained using the formula,

Number of Hours, x Frequency, f
1 20 -3.125 9.766 195.313
2 37 -2.125 4.516 167.078
3 49 -1.125 1.266 62.016
4 39 -0.125 0.016 0.609
5 33 0.875 0.766 25.266
6 17 1.875 3.516 59.766
7 3 2.875 8.266 24.797
8 34 3.875 15.016 510.531
Total 232 1045.375

b-2)

A typical customer parked with mean value = 4.125 hours.

c)

The mean for the amount charged is,

Amount Charged Frequency, f
3 20 60
7 37 259
10 49 490
17 39 663
21 33 693
25 17 425
27 3 81
31 34 1054
Total 232 3725

The standard deviation for the amount charged is,

Amount Charged Frequency, f
3 20 -13.056 170.460 3409.201
7 37 -9.05603 82.012 3034.435
10 49 -6.05603 36.676 1797.102
17 39 0.943966 0.891 34.752
21 33 4.943966 24.443 806.612
25 17 8.943966 79.995 1359.907
27 3 10.94397 119.770 359.311
31 34 14.94397 223.322 7592.952
Total 232 18394.272


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