Question

In: Statistics and Probability

The Downtown Parking Authority of Tampa, Florida, reported the following information for a sample of 231...

The Downtown Parking Authority of Tampa, Florida, reported the following information for a sample of 231 customers on the number of hours cars are parked and the amount they are charged.

Number of Hours Frequency Amount Charged
1 22 $ 3
2 38 6
3 51 8
4 45 12
5 20 14
6 14 16
7 5 18
8 36 22
231

a-2. Is this a discrete or a continuous probability distribution?

b-1. Find the mean and the standard deviation of the number of hours parked. (Do not round the intermediate calculations. Round your final answers to 3 decimal places.)

b-2. How long is a typical customer parked? (Do not round the intermediate calculations. Round your final answer to 3 decimal places.)

Find the mean and the standard deviation of the amount charged. (Do not round the intermediate calculations. Round your final answers to 3 decimal places.)

Solutions

Expert Solution

a-2)

discrete

b-1)

x P(x) xP(x) x2*P(x)
1 0.095 0.095 0.095
2 0.165 0.330 0.660
3 0.221 0.663 1.989
4 0.195 0.780 3.120
5 0.087 0.435 2.175
6 0.061 0.366 2.196
7 0.022 0.154 1.078
8 0.156 1.248 9.984
4.071 21.297
E(x) =μ= ΣxP(x) = 4.071
E(x2) = Σx2P(x) = 21.297
Var(x)=σ2 = E(x2)-(E(x))2= 4.724
std deviation=         σ= √σ2 = 2.173

from above

mean =4.071

standard deviation =2.173

b-2) typical customer parked =11.314

c)

x P(x) xP(x) x2*P(x)
3 0.095 0.285 0.855
6 0.165 0.990 5.940
8 0.221 1.768 14.144
12 0.195 2.340 28.080
14 0.087 1.218 17.052
16 0.061 0.976 15.616
18 0.022 0.396 7.128
22 0.156 3.432 75.504
11.405 164.319
E(x) =μ= ΣxP(x) = 11.405
E(x2) = Σx2P(x) = 164.319
Var(x)=σ2 = E(x2)-(E(x))2= 34.245
std deviation=         σ= √σ2 = 5.852

mean =11.405

standard deviation =5.852


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