Proof on Thales theorem :
If a line is drawn parallel to one side of a triangle and it
intersects the other two sides at two distinct points then it
divides the two sides in the same ratio.
Given : In ∆ABC , DE || BC and intersects AB in D
and AC in E.
Prove that : AD / DB = AE / EC
Construction : Join BC,CD and draw EF ┴ BA and DG
┴ CA.
Statements
|
Reasons
1) EF ┴ BA |
1) Construction |
2) EF is the height of ∆ADE and
∆DBE |
2) Definition of
perpendicular |
3)Area(∆ADE) = (AD
.EF)/2 |
3)Area = (Base
.height)/2 |
4)Area(∆DBE)
=(DB.EF)/2 |
4) Area = (Base
.height)/2 |
5)(Area(∆ADE))/(Area(∆DBE)) =
AD/DB |
5) Divide (4) by (5) |
6) (Area(∆ADE))/(Area(∆DEC)) =
AE/EC |
6) Same as above |
7) ∆DBE ~∆DEC |
7) Both the ∆s are on the same
base and
between the same || lines. |
8)
Area(∆DBE)=area(∆DEC) |
8) If the two triangles are
similar their
areas are equal |
9) AD/DB =AE/EC |
9) From (5) and (6) and
(7) |
|