Proof on Thales theorem :
If a line is drawn parallel to one side of a triangle and it
intersects the other two sides at two distinct points then it
divides the two sides in the same ratio.
Given : In ∆ABC , DE || BC and intersects AB in D
and AC in E.
Prove that : AD / DB = AE / EC
Construction : Join BC,CD and draw EF ┴ BA and DG
┴ CA. 
| 
 Statements 
 | 
| 
 Reasons 
| 1) EF ┴ BA | 
 
| 1) Construction | 
 
| 2) EF is the height of ∆ADE and
∆DBE | 
 
| 2) Definition of
perpendicular | 
 
| 3)Area(∆ADE) = (AD
.EF)/2 | 
 
| 3)Area = (Base
.height)/2 | 
 
| 4)Area(∆DBE)
=(DB.EF)/2 | 
 
| 4) Area = (Base
.height)/2 | 
 
| 5)(Area(∆ADE))/(Area(∆DBE)) =
AD/DB | 
 
| 5) Divide (4) by (5) | 
 
| 6) (Area(∆ADE))/(Area(∆DEC)) =
AE/EC | 
 
| 6) Same as above | 
 
| 7) ∆DBE ~∆DEC | 
 
7) Both the ∆s are on the same
base and 
between the same || lines. | 
 
| 8)
Area(∆DBE)=area(∆DEC) | 
 
8) If the two triangles are
similar their 
areas are equal | 
 
| 9) AD/DB =AE/EC | 
 
| 9) From (5) and (6) and
(7) | 
 
 
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