Question

In: Computer Science

In C 1- Use nested for loops to create an addition lookup table. Fill in an...

In C

1- Use nested for loops to create an addition lookup table. Fill in an array and print out the following table showing the sum of the row and column numbers 0-9.

0  1  2  3  4..   <- column numbers   
1  2  3  4  5..   
2  3  4  5  6..  <- These nos. = Row + Column   
3  4  5  6  7..  <- for example 7 = 3 + 4   
4  5  6  7  8.. 
...   
^Row numbers

2- use

A hexadecimal version 16x16 table 0-F. Use print specifier %x to print numbers in hex instead of decimal.

Solutions

Expert Solution

(1)

C Program:

/* C Program that prints addition look up table */

#include <stdio.h>
#include <stdlib.h>

//Main program
int main()
{
    int i,j;

    printf("\n");

    //Printing starting row (Row number)
    for(i=0; i<=9; i++)
    {
        //Printing row number
        printf(" %-4d ", i);
    }

    //Iterating over remaining rows
    for(i=1; i<=9; i++)
    {
        //Printing row number
        printf("\n %-4d ", i);

        //Iterating over columns
        for(j=1; j<=9; j++)
        {
            //Printing column values
            printf(" %-4d ", (i+j));
        }
    }

    printf("\n\n");
    return 0;
}

--------------------------------------------------------------------------------------------------------------------------------------------------------------------

Sample Output:

_____________________________________________________________________________________________

(2)

/* C Program that prints hexadecimal numbers */

#include <stdio.h>
#include <stdlib.h>

//Main program
int main()
{
    int i, j;

    printf("\n %4c ", '+');

    //Printing starting row
    for (i = 0; i < 16; i++)
    {
        //Printing row
        printf(" %4X ", i);
    }

    //Printing decimal and equivalent hexadecimal numbers

    //Printing rows
    for (i=0; i<16; i++)
    {
        //Printing row
        printf("\n %4X ", i);

        for(j=0; j<16; j++)
        {
            //Printing value
            printf(" %4X ", (i+j));
        }
    }

    printf("\n\n");
    return 0;
}

Sample Output:


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