In: Economics
A new magnetic crane for the junkyard will cost $120000 and will generate $27000 revenue per year for 6 years. The salvage value will be $30000 after the 6 years. Assume the equipment has a 7% MARR.
a) Determine the IRR for the machine. Please use interpolation.
b) Since the company requires at least 5% return on their investment, should the machine be purchased? Why?
a) IRR using Interpolation method,
The formula = L+((NPVL)/(NPVL-NPVH)*(H-L))
Where,
L = lower rate of interest
H = higher rate of interest
NPVL = NPV at lower rate if interest
NPVH = NPV at higher rate if interest
NPVL =
Year |
Cash flow |
Discount factor (7%) |
PV |
0 |
-120000 |
1.00 |
-120000 |
1 |
27000 |
0.93 |
25234 |
2 |
27000 |
0.87 |
23583 |
3 |
27000 |
0.82 |
22040 |
4 |
27000 |
0.76 |
20598 |
5 |
27000 |
0.71 |
19251 |
6 |
57000 |
0.67 |
37982 |
NPV |
28687 |
NPVH =
Year |
Cashflow |
Discount factor(15%) |
PV |
0 |
-120000 |
1.00 |
-120000 |
1 |
27000 |
0.87 |
23478 |
2 |
27000 |
0.76 |
20416 |
3 |
27000 |
0.66 |
17753 |
4 |
27000 |
0.57 |
15437 |
5 |
27000 |
0.50 |
13424 |
6 |
57000 |
0.43 |
24643 |
NPV |
-4849 |
IRR = 0.07+(28687/(28687-(-4849.17))*(0.15-0.07)) = 13.84%
b) Yes the machine can be purchased as the IRR from the investment 13.84% which is greater than minimum rate of return 5%