In: Economics
A new magnetic crane for the junkyard will cost $120000 and will generate $27000 revenue per year for 6 years. The salvage value will be $30000 after the 6 years. Assume the equipment has a 7% MARR.
a) Determine the IRR for the machine. Please use interpolation.
b) Since the company requires at least 5% return on their investment, should the machine be purchased? Why?
a) IRR using Interpolation method,
The formula = L+((NPVL)/(NPVL-NPVH)*(H-L))
Where,
L = lower rate of interest
H = higher rate of interest  
NPVL = NPV at lower rate if interest
NPVH = NPV at higher rate if interest
NPVL =
| 
 Year  | 
 Cash flow  | 
 Discount factor (7%)  | 
 PV  | 
| 
 0  | 
 -120000  | 
 1.00  | 
 -120000  | 
| 
 1  | 
 27000  | 
 0.93  | 
 25234  | 
| 
 2  | 
 27000  | 
 0.87  | 
 23583  | 
| 
 3  | 
 27000  | 
 0.82  | 
 22040  | 
| 
 4  | 
 27000  | 
 0.76  | 
 20598  | 
| 
 5  | 
 27000  | 
 0.71  | 
 19251  | 
| 
 6  | 
 57000  | 
 0.67  | 
 37982  | 
| 
 NPV  | 
 28687  | 
NPVH =
| 
 Year  | 
 Cashflow  | 
 Discount factor(15%)  | 
 PV  | 
| 
 0  | 
 -120000  | 
 1.00  | 
 -120000  | 
| 
 1  | 
 27000  | 
 0.87  | 
 23478  | 
| 
 2  | 
 27000  | 
 0.76  | 
 20416  | 
| 
 3  | 
 27000  | 
 0.66  | 
 17753  | 
| 
 4  | 
 27000  | 
 0.57  | 
 15437  | 
| 
 5  | 
 27000  | 
 0.50  | 
 13424  | 
| 
 6  | 
 57000  | 
 0.43  | 
 24643  | 
| 
 NPV  | 
 -4849  | 
IRR = 0.07+(28687/(28687-(-4849.17))*(0.15-0.07)) = 13.84%
b) Yes the machine can be purchased as the IRR from the investment 13.84% which is greater than minimum rate of return 5%