Question

In: Statistics and Probability

This week we will look at the test for goodness of fit. In order to complete...

This week we will look at the test for goodness of fit. In order to complete this discussion board, you will need a small bag of plain m&m’s.   M&m’s have six colors, listed below. The Mars Candy Company has published the percentage of each color that we should see in any given bag of m&m’s. We are going to determine if our purchases m&m’s are significantly different from what we should expect.

Our Null Hypothesis is that our percentages will match those provided by the company.

Our Alternate Hypothesis is that our percentages will not match those provided by the company.

Step 2:

Average your information with the information from two other students (three students total). This information is the OBSERVED data.

Observed data to be averaged:

  • Color Blue Orange Green Yellow Red Brown Total
    Number of M&M's 5 16 19 5 4 6 55
    Percent of Total 9% 29% 35%

    9%

    7% 11% 100%

    Color

    Blue

    Orange

    Green

    Yellow

    Red

    Brown

    Total

    # of M&Ms

    24

    22

    27

    13

    7

    10

    103

    % of Total

    23%

    21%

    26%

    13%

    7%

    10%

    100%

  • Color

    Blue

    Orange

    Green

    Yellow

    Red

    Brown

    Total

    Number of m&m’s

    13

    5

    3

    10

    9

    5

    45

    Percent of Total

    29%

    12%

    7%

    21%

    20%

    12%

    100%

The EXPECTED data is published by the Mars Candy Company and is listed below:

Color

Blue

Orange

Green

Yellow

Red

Brown

Total

Percent of Total

24%

20%

16%

14%

13%

13%

100%

Calculate the chi-square statistic using the formula on page 656 in your book, or use your calculator.

Then using a 0.05 level of significance and 5 degrees of freedom (because there are 6 colors), determine if we reject our Null Hypothesis or not.  

Solutions

Expert Solution

Result:

Average your information with the information from two other students (three students total). This information is the OBSERVED data.

Observed data to be averaged:

·

Color

Blue

Orange

Green

Yellow

Red

Brown

Total

Number of M&M's

5

16

19

5

4

6

55

Percent of Total

9%

29%

35%

9%

7%

11%

100%

Color

Blue

Orange

Green

Yellow

Red

Brown

Total

# of M&Ms

24

22

27

13

7

10

103

% of Total

23%

21%

26%

13%

7%

10%

100%

·

Color

Blue

Orange

Green

Yellow

Red

Brown

Total

Number of m&m’s

13

5

3

10

9

5

45

Percent of Total

29%

12%

7%

21%

20%

12%

100%

The EXPECTED data is published by the Mars Candy Company and is listed below:

Color

Blue

Orange

Green

Yellow

Red

Brown

Total

Percent of Total

24%

20%

16%

14%

13%

13%

100%

Calculate the chi-square statistic using the formula on page 656 in your book, or use your calculator.

Then using a 0.05 level of significance and 5 degrees of freedom (because there are 6 colors), determine if we reject our Null Hypothesis or not.  

Total observed

expected%

expected

Blue

5

24

13

42

(42/100)*203=24

48.72

Orange

16

22

5

43

(43/100)*203=20

40.6

Green

19

27

3

49

(49/100)*203=16

32.48

Yellow

5

13

10

28

(28/100)*203=14

28.42

Red

4

7

9

20

(20/100)*203=13

26.39

Brown

6

10

5

21

(21/100)*203=13

26.39

Total

55

103

45

203

203

Goodness of Fit Test

observed

expected

O - E

(O - E)² / E

42

48.720

-6.720

0.927

43

40.600

2.400

0.142

49

32.480

16.520

8.402

28

28.420

-0.420

0.006

20

26.390

-6.390

1.547

21

26.390

-5.390

1.101

Total

203

203.000

0.000

12.126

12.126

chi-square

5

df

Critical chi square value with 5 df at 0.05 level =11.07

Calculated chi square 12.126 > critical chi square value 11.07.

Ho is rejected.

There is enough evidence to conclude that our percentages will not match those provided by the company.


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