Question

In: Statistics and Probability

Apply the χ2 goodness‐of‐fit test to the data in column 1 and test the assumption of...

Apply the χ2 goodness‐of‐fit test to the data in column 1 and test the assumption of a normal distribution.

Measured Force Data for Exercise Problems

F (N) Set 1 F (N) Set 2 F (N) Set 3
51.9 51.9 51.1
51.0 48.7 50.1
50.3 51.1 51.4
49.6 51.7 50.5
51.0 49.9 49.7
50.0 48.8 51.6
48.9 52.5 51.0
50.5 51.7 49.5
50.9 51.3 52.4
52.4 52.6 49.5
51.3 49.4 51.6
50.7 50.3 49.4
52.0 50.3 50.8
49.4 50.2 50.8
49.7 50.9 50.2
50.5 52.1 50.1
50.7 49.3 52.3
49.4 50.7 48.9
49.9 50.5 50.4
49.2 49.7 51.5

Solutions

Expert Solution

The Chi-Square goodness of fit test to test whether the normality assumption is true for column 1 is performed in following steps in excel.

Step 1: Write the data value in excel. The screenshot is shown below,

Step 2: The mean and standard deviation for the data values are obtained using the excel functions =AVERAGE() and STDEV(). The screenshot is shown below,

Step 3: The Z score for each data values are obtained using the formula,

The screenshot is shown below,

Step 4: The observed value are obtained by counting the Z score as follows,

The observed values are,

Observed values
Z score Count
Z<-1 4
-1<Z<0 5
0<Z<1 8
Z>1 3

Step 5: The expected values are obtained in excel. The screenshot is shown below,

The expected values are,

Expected values
Z score Count
Z<-1 3.173
-1<Z<0 6.827
0<Z<1 6.827
Z>1 3.173

Step 6: The Chi-Square statistic is obtained using the formula,

Z score Observed, Expected,
Z<-1 4 3.173 0.827 0.684 0.215
-1<Z<0 5 6.827 -1.827 3.338 0.489
0<Z<1 8 6.827 1.173 1.376 0.202
Z>1 3 3.173 -0.173 0.030 0.009
Sum 0.915

Step 7: The P-value for the chi square is obtained for chi square = 0.915 and degree of freedom = k - 1 = 4 - 1 = 3 using the excel function =1-CHISQ.DIST(0.915,3,TRUE)

Conclusion:

at 5% significance level. it can be concluded that the null hypothesis is not rejected. Hence we can conclude that the data values are normally distributed.


Related Solutions

Test the following hypotheses by using the χ2 goodness of fit test.
You may need to use the appropriate technology to answer this question. Test the following hypotheses by using the χ2 goodness of fit test. H0: pA = 0.40, pB = 0.40, and pC = 0.20 Ha: The population proportions are not pA = 0.40, pB = 0.40, and pC = 0.20. A sample of size 200 yielded 60 in category A, 120 in category B, and 20 in category C. Use α = 0.01 and test to see whether the...
Test the following hypotheses by using the χ2 goodness of fit test. H0: pA = 0.40,...
Test the following hypotheses by using the χ2 goodness of fit test. H0: pA = 0.40, pB = 0.40, and pC = 0.20 Ha: The population proportions are not pA = 0.40, pB = 0.40, and pC = 0.20. A sample of size 200 yielded 60 in category A, 20 in category B, and 120 in category C. Use α = 0.01 and test to see whether the proportions are as stated in H0. (a) Use the p-value approach. Find...
Question 1 The Goodness of Fit test and the Test of Independence are two forms of...
Question 1 The Goodness of Fit test and the Test of Independence are two forms of which of the following test? (2 points) Regression analysis Correlation analysis Chi-square analysis Independent samples t-test Related samples t-test We can make cause-and-effect statements when: (2 points) We run correlations to see how two variables are related to one another We use experimental manipulations (i.e., through the manipulation of the independent variable) What type of question do chi-squares answer? (2 points) Can we predict...
Given a data set with 100 observations, a goodness of fit test to see if a...
Given a data set with 100 observations, a goodness of fit test to see if a sample follows a uniform distribution or a poisson distribution or a normal distribution will have the same number of degrees of freedom. true or false and When a contingency table of expected frequencies is constructed, the null hypothesis is that all of the cells in the table are equally likely. true or false thank you :)
Using the following data (already sorted), use a goodness of fit test to test whether it...
Using the following data (already sorted), use a goodness of fit test to test whether it comes from an exponential distribution. The exponential distribution has one parameter, its mean, μ (which is also its standard deviation). The exponential distribution is a continuous distribution that takes on only positive values in the interval (0,∞). Probabilities for the exponential distribution can be found based on the following probability expression: . Use 10 equally likely cells for your goodness of fit test. Data...
Use the chi-square test for goodness of fit to determine if the data shown below are...
Use the chi-square test for goodness of fit to determine if the data shown below are consistent with an inheritance pattern of simple dominance. Use p = 0.05 for determining significance. Cross: Aa x Aa Offspring: 70 dominant phenotype 30 recessive phenotype A. The data are consistent with a simple dominance pattern of inheritance. B. The data are not consistent with a simple dominance pattern of inheritance.
Compare the Goodness of Fit Test and the Test for Independence in terms of the number...
Compare the Goodness of Fit Test and the Test for Independence in terms of the number of variables and levels of those that can be compared. In what ways are they similar or different? (3 points)
1) What’s the difference among the chi-square test for goodness of fit, the chi-square test for...
1) What’s the difference among the chi-square test for goodness of fit, the chi-square test for independence, and the chi-square test for homogeneity 2) State the requirements to perform a chi-square test
1/You are conducting a multinomial Goodness of Fit hypothesis test for the claim that the 4...
1/You are conducting a multinomial Goodness of Fit hypothesis test for the claim that the 4 categories occur with the following frequencies: HoHo : pA=0.25pA=0.25;  pB=0.4pB=0.4;  pC=0.1pC=0.1;  pD=0.25pD=0.25 Complete the table. Report all answers accurate to three decimal places. Category Observed Frequency Expected Frequency A 20 B 33 C 4 D 26 What is the chi-square test-statistic for this data? (2 decimal places) χ2=( ) What is the P-Value? (3 decimal places) P-Value = ( ) For significance level alpha 0.025, What would...
This week we will look at the test for goodness of fit. In order to complete...
This week we will look at the test for goodness of fit. In order to complete this discussion board, you will need a small bag of plain m&m’s.   M&m’s have six colors, listed below. The Mars Candy Company has published the percentage of each color that we should see in any given bag of m&m’s. We are going to determine if our purchases m&m’s are significantly different from what we should expect. Our Null Hypothesis is that our percentages will...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT