Question

In: Computer Science

Create a JAVA code program: Huffman code will be converted to its text equivalent Output an...

Create a JAVA code program:

Huffman code will be converted to its text equivalent

Output an error message if the input cannot be converted

I can give an thumbs up! :)

Solutions

Expert Solution

Algorithm:

create a priority queue Q consisting of each unique character.
sort then in ascending order of their frequencies.
for all the unique characters:
    create a newNode
    extract minimum value from Q and assign it to leftChild of newNode
    extract minimum value from Q and assign it to rightChild of newNode
    calculate the sum of these two minimum values and assign it to the value of newNode
    insert this newNode into the tree
return rootNode

Implementation:

// Huffman Coding in Java

import java.util.PriorityQueue;
import java.util.Comparator;

class HuffmanNode {
int item;
char c;
HuffmanNode left;
HuffmanNode right;
}

// For comparing the nodes
class ImplementComparator implements Comparator<HuffmanNode> {
public int compare(HuffmanNode x, HuffmanNode y) {
    return x.item - y.item;
}
}

// IMplementing the huffman algorithm
public class Huffman {
public static void printCode(HuffmanNode root, String s) {
    if (root.left == null && root.right == null && Character.isLetter(root.c)) {

      System.out.println(root.c + "   | " + s);

      return;
    }
    else{
    System.out.println("Error !!! Cannot convert to huffman code !");}
    printCode(root.left, s + "0");
    printCode(root.right, s + "1");
}

public static void main(String[] args) {

    int n = 4;
    char[] charArray = { 'A', 'B', 'C', 'D' };
    int[] charfreq = { 5, 1, 6, 3 };

    PriorityQueue<HuffmanNode> q = new PriorityQueue<HuffmanNode>(n, new ImplementComparator());

    for (int i = 0; i < n; i++) {
      HuffmanNode hn = new HuffmanNode();

      hn.c = charArray[i];
      hn.item = charfreq[i];

      hn.left = null;
      hn.right = null;

      q.add(hn);
    }

    HuffmanNode root = null;

    while (q.size() > 1) {

      HuffmanNode x = q.peek();
      q.poll();

      HuffmanNode y = q.peek();
      q.poll();

      HuffmanNode f = new HuffmanNode();

      f.item = x.item + y.item;
      f.c = '-';
      f.left = x;
      f.right = y;
      root = f;

      q.add(f);
    }
    System.out.println(" Char | Huffman code ");
    System.out.println("--------------------");
    printCode(root, "");
}
}


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