Question

In: Computer Science

(C++)Set hasDigit to true if the 3-character passCode contains a digit.

C++. Set hasDigit to true if the 3-character passCode contains a digit.

#include
#include
#include
using namespace std;

int main() {
bool hasDigit;
string passCode;

hasDigit = false;
cin >> passCode;

/* Your solution goes here */

if (hasDigit) {
cout << "Has a digit." << endl;
}
else {
cout << "Has no digit." << endl;
}

return 0;

Solutions

Expert Solution

// Declare required header file
 
// iostream is used for input output
 
#include 
 
// string is used to use string type
 
// character
 
#include 
 
// This header file use here for
 
// using the isdigit() function
 
// to check digits is exist or not
 
#include 
 
// Namespace std for cin cout
 
using namespace std;
 
// Create a main function of the
 
// program
 
int main()
 
{
 
// Declare hadDigit is a Boolean
 
// variable
 
bool hasDigit;
 
// Declare passCode is a string character
 
string passCode;
 
// Initially hasDigit Declare
 
// false statement
 
hasDigit = false;
 
// Prompt the passcode from console
 
cin >> passCode;
 
/* Your solution goes here */
 
// Declare the position of 3 digits
 
// passCode.at(hold the input position value)
 
// It means passCode.at() find out the value form that position.
 
// Assign the input value to digit1 from index 0
 
int digit1 = passCode.at(0);
 
// Assign the input value to digit2 from index 1
 
int digit2 = passCode.at(1);
 
// Assign the input value to digit3 from index 2
 
int digit3 = passCode.at(2);
 
// When anyone digits(digit1, digit2,digit3) contains a digit
 
if(isdigit(digit1) || isdigit(digit2) || isdigit(digit3))
 
   {
 
     // Set hasDigit to true
 
       hasDigit = true;
 
   }
 
   // When hasDigit contains true
 
if (hasDigit) {
 
// Display has a digit
 
cout << "Has a digit." << endl;
 
}
 
// Otherwise it has no digit
 
else {
 
cout << "Has no digit." << endl;
 
}
 
return 0;
 
}

Expert Solution

The following information has been provided for the question above:

  • "Screen shot of C++ code" for your understanding.
  • "Text format code" to copy and execute in your IDE.

Screen shot of C++ code:

Output:

Text format code:

// Header files section
#include <iostream>
#include <cctype>
#include <string>
using namespace std;

//Program begins with a main function
int main()
{
//Declare variable
string passCode;
//Initialize the variables
bool hasDigit = false;
passCode = "abc";

//Set hasDigit to true if the 3-character
//passCode contains a digit.
if (isdigit(passCode.at(0)) || isdigit(passCode.at(1))
  || isdigit(passCode.at(2)))
{
  hasDigit = true;
}
if (hasDigit)
{
  cout << "Has a digit." << endl;
}
else
{
  cout << "Has no digit." << endl;
}
return 0;
}


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