Question

In: Statistics and Probability

What is probability that randomly selected 3-digit number (from 100 through 999) contains at least one...

What is probability that randomly selected 3-digit number (from 100 through 999) contains at least one of the digits 2 or 5?

Solutions

Expert Solution

Total three digit numbers possible = 10*10*10 = 1000

Number of three digit numbers without 2 or 5 = 8*8*8 = 512

Hence,

P(Randomly selected 3-digit number contains at least one of the digits 2 or 5)

= 1 - 512/1000

= 0.488

orchestra answered 2 years ago
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