Question

a. How many 3-digit numbers can you make using the digits from the set of (3, 4, 5, 6, 8, 2, 7) without repetitions?

b. How many numbers can be made with the digits from the set of (0, 3, 5, 7, 8, 4, 9), which are greater than 0 and less than a thousand (repetitions are allowed)?

Answer 1

a. 2, 3, 4,5,6,7,8 by Here we have 7digits. We have to form 3-digits number from the given 7-digits without repetation. 76. T arrangment of 3-digits. L no of ways we group 3-digits ¥! xal= # 586*7= 210 Ang 3l4l 6. (0,3,5,7,8, 4, 97 Here, we have 7 - digits... We have to form numbers. which are greater than o and less than 1000 by repetation of digits. So here we deal with 1-degit, 2-digit and 3-digit number. case: (1-digit) 6 ways. Case: 2 So, Ans. (2-digit) 6 + 42+294 = 34 Get Tways = 42ways case: 3 (3-digit) 6 727=294 ways because o is not included in thousand place in 3-digit number EXPLANATION