1. At high noon, a sinusoidal electromagnetic wave is heading straight toward San Diego. At a...

1. At high noon, a sinusoidal electromagnetic wave is heading straight toward San Diego. At a 12:00 sharp, the electric field at a certain location is 700 N/C directed South. a) What is the magnitude and direction of the magnetic field at this location at this instant? b) If it takes 1.0 x 10^-15 seconds for the fields at this location to return to the values described above, what is the wavelength of this wave? c) Does this wave fall within the visible range? d) At what rate does this wave deliver energy to a patch of Earth of area 2 m², assuming all is absorbed?

Expert Solution

a) The electric field's direction, magnetic field's direction and the direction of propagation of the wave are mutually perpendicular to each other. And the cross product of the electric field's direction with magnetic field's direction gives the direction of propagation. Assuming the wave is coming down from above, the electric's field's direction is towards south, then the magnetic field's direction is towards east.

The magnitude of magnetic field is

where E is the magnitude of electric field and c is the speed of light

b) Given the time period is 1.0 x 10^-15 s

The wavelength is

c) The shortest visible wavelength is 350 nm which is of violet light. Thus 47.7 nm wave is not within visible range.

d) The average Poynting vector is

The rate at which this wave deliver energy to a patch of Earth of area A is

genius_generous answered 2 years ago

A sinusoidal electromagnetic wave of frequency 6.10

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