You are looking at a current carrying wire. The current is heading straight for you toward your eye. The magnetic field lines and field strength are best described by: The field lines point in away from wire, and drop off as \(1 / r^{2}\)The field lines wrap around the wire CCW and drop off as \(1 / \mathrm{r}\)The field lines wrap around the wire CCW and drop off as \(1 / r^{2}\)The field lines point in toward wire, and drop off as \(1 / \mathrm{r}\)The field lines wrap around the wire \(\mathrm{CW}\) and drop off as \(1 / \mathrm{r}\)The field lines point in toward wire, and drop off as \(1 / r^{2}\)The field lines point in away from wire, and drop off as \(1 / \mathrm{r}\)The field lines wrap around the wire \(\mathrm{CW}\) and drop off as \(1 / \mathrm{r}^{2}\)

Question

In: Physics

You are looking at a current carrying wire. The current is heading straight for you toward your eye.

You are looking at a current carrying wire. The current is heading straight for you toward your eye. The magnetic field lines and field strength are best described by:

The field lines point in away from wire, and drop off as \(1 / r^{2}\)

The field lines wrap around the wire CCW and drop off as \(1 / \mathrm{r}\)

The field lines wrap around the wire CCW and drop off as \(1 / r^{2}\)

The field lines point in toward wire, and drop off as \(1 / \mathrm{r}\)

The field lines wrap around the wire \(\mathrm{CW}\) and drop off as \(1 / \mathrm{r}\)

The field lines point in toward wire, and drop off as \(1 / r^{2}\)

The field lines point in away from wire, and drop off as \(1 / \mathrm{r}\)

The field lines wrap around the wire \(\mathrm{CW}\) and drop off as \(1 / \mathrm{r}^{2}\)

Expert Solution

genius_generous answered 2 years ago

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