In: Statistics and Probability
The system manager wants to know whether the mean response time to a specific type of command exceeds 82 millisec.
Let X be the random variable which takes the response time of a distributed computer system.
Let's write the given information
n = sample size = 25
= sample mean = 84.25
s = sample standard deviation = 10
Level of significance = = 0.05
Here we want to know whether the mean response time to a specific type of command exceeds 82 millisec.
So the
the null hypothesis ( H0 ) and the alternative hypothesis ( Ha ) are as follows:
From the alternative hypothesis the given test is right tailed test
Hypothesis testing
Here population standard deviation is not given and we use sample standard deviation(s) instead of population
standard deviation . Also sample size is not sufficiently large( >= 30) so we can assume the X follows normal distribution so we can use one sample t test.
Using minitab we get following result
The command is Stat>>>Basic Statistics >>1 sample t...
Select summary Statistics and fill the required information.
then click on Perform hypothesis test enter hypothesis mean (82)
Look the following image:
then click on Option select level of confidence = (1 - alpha)*100 = (1 - 0.05)*100 = 95.0
Alternative " greater than"
then click on Ok
We get the following output
From the above output
ii) t test statistic value = 1.13
p- value = 0.136
iii) Decision rule: 1) If p-value < level of significance (alpha) then we reject null hypothesis
2) If p-value > level of significance (alpha) then we fail to reject null hypothesis.
Here p value = 0.136 > 0.05 so we used first rule.
That is we fail to reject null hypothesis and accept alternative hypothesis.
At 5% level of significance we don't have sufficient evidence to conclude that the mean response time to a specific type of command exceeds 82 millisec .
b) Do the same process except select not equal instead of greater than in Alternative.
So we get the output as:
from the above output the 95% two-sided confidence interval on the mean response time is (80.12, 88.38)